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Shubham Jakhar Class 10 trainer in Sikar

Shubham Jakhar

Graduate with 1 year experience of tutoring.

Shivsinghpura, Sikar, India - 332001.

Verified 1 Student

Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

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Education

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Overview

I have completed BTech in civil engineering in 2017. I am currently a SSC CGL aspirant. So far I have one year experience in giving home tuitions for Maths (CBSE) to students of 7th to 10th class students. After getting positive feedback from them I have come on this platform.

Languages Spoken

Hindi Mother Tongue (Native)

English Basic

Education

SKIT Jaipur 2017

Bachelor of Technology (B.Tech.)

Address

Shivsinghpura, Sikar, India - 332001

Verified Info

ID Verified

Education Verified

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Teaches

Class 10 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

1

Board

CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

Class 9 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

1

Board

CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

No

Class 8 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

No

Class 7 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

No

Class 11 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

No

Teaching Experience in detail in Class 11 Tuition

Till now I've given tuitions to students of upto class 10th. I can educate the student according to his/her background, taste and capability because of good communication as well as management skills. With marks I have also enhanced calculation speed of my students in the past.

Class 6 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

1

Board

CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

No

Class 12 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

No

Teaching Experience in detail in Class 12 Tuition

I have given tuitions to students of upto class 10th till now. With better communication and management skills I can teach student according to his/her background and capability.

Reviews

No Reviews yet! Be the first one to Review

FAQs

1. Which school boards of Class 10 do you teach for?

CBSE

2. Do you have any prior teaching experience?

Yes

3. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 1 year.

Answers by Shubham Jakhar (27)

Answered on 16/10/2019 Learn CBSE/Class 9/Mathematics/Unit 4-Geometry/Circles/NCERT Solutions/Exercise 10.5

∠CAD = ∠CPQ( angles subtended by same arc BC in a circle are same) Similarly, ∠ADC = ∠PQC therefore in triangles ACD and PCQ, ∠PCQ = ∠ACD Now subtracting ∠PCD from both we get, ∠ACP = ∠QCD ...more

∠CAD = ∠CPQ( angles subtended by same arc BC in a circle are same)

Similarly, ∠ADC = ∠PQC

therefore in triangles ACD and PCQ,

∠PCQ = ∠ACD

Now subtracting ∠PCD from both we get,

∠ACP = ∠QCD

 

Answers 2 Comments
Dislike Bookmark

Answered on 16/10/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.8

(i) (4πr^3)/3 = 4 x 22/7 x 7 x 7 x 7/3 = 1437.33 cubic cm (ii) 4/3 x 22/7 x 0.63 x 0.63 x 0.63 = 1.0478 cubic m
Answers 2 Comments
Dislike Bookmark

Answered on 15/10/2019 Learn CBSE/Class 9/Science/Unit 3-Motion, Force and Work/Motion/NCERT Solutions/NCERT Exercise 8

Let distance=dTime = t1 for goingTime= t2 for coming backt1=d/20t2=d/30Total distance=2dTotal time = t1+t2Avg speed = distance/time = 2d/(d/20 + d/30) = 24 m/s ...more

Let distance=d
Time = t1 for going
Time= t2 for coming back
t1=d/20
t2=d/30
Total distance=2d
Total time = t1+t2
Avg speed = distance/time
                    = 2d/(d/20 + d/30)
                    = 24 m/s

Answers 2 Comments
Dislike Bookmark

Teaches

Class 10 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

1

Board

CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

Class 9 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

1

Board

CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

No

Class 8 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

No

Class 7 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

No

Class 11 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

No

Teaching Experience in detail in Class 11 Tuition

Till now I've given tuitions to students of upto class 10th. I can educate the student according to his/her background, taste and capability because of good communication as well as management skills. With marks I have also enhanced calculation speed of my students in the past.

Class 6 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

1

Board

CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

No

Class 12 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

No

Teaching Experience in detail in Class 12 Tuition

I have given tuitions to students of upto class 10th till now. With better communication and management skills I can teach student according to his/her background and capability.

No Reviews yet! Be the first one to Review

Answers by Shubham Jakhar (27)

Answered on 16/10/2019 Learn CBSE/Class 9/Mathematics/Unit 4-Geometry/Circles/NCERT Solutions/Exercise 10.5

∠CAD = ∠CPQ( angles subtended by same arc BC in a circle are same) Similarly, ∠ADC = ∠PQC therefore in triangles ACD and PCQ, ∠PCQ = ∠ACD Now subtracting ∠PCD from both we get, ∠ACP = ∠QCD ...more

∠CAD = ∠CPQ( angles subtended by same arc BC in a circle are same)

Similarly, ∠ADC = ∠PQC

therefore in triangles ACD and PCQ,

∠PCQ = ∠ACD

Now subtracting ∠PCD from both we get,

∠ACP = ∠QCD

 

Answers 2 Comments
Dislike Bookmark

Answered on 16/10/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.8

(i) (4πr^3)/3 = 4 x 22/7 x 7 x 7 x 7/3 = 1437.33 cubic cm (ii) 4/3 x 22/7 x 0.63 x 0.63 x 0.63 = 1.0478 cubic m
Answers 2 Comments
Dislike Bookmark

Answered on 15/10/2019 Learn CBSE/Class 9/Science/Unit 3-Motion, Force and Work/Motion/NCERT Solutions/NCERT Exercise 8

Let distance=dTime = t1 for goingTime= t2 for coming backt1=d/20t2=d/30Total distance=2dTotal time = t1+t2Avg speed = distance/time = 2d/(d/20 + d/30) = 24 m/s ...more

Let distance=d
Time = t1 for going
Time= t2 for coming back
t1=d/20
t2=d/30
Total distance=2d
Total time = t1+t2
Avg speed = distance/time
                    = 2d/(d/20 + d/30)
                    = 24 m/s

Answers 2 Comments
Dislike Bookmark

Contact

Load More

Shubham Jakhar describes himself as Graduate with 1 year experience of tutoring.. He conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Shubham is located in Shivsinghpura, Sikar. Shubham takes at students Home. He has 1 years of teaching experience . Shubham has completed Bachelor of Technology (B.Tech.) from SKIT Jaipur in 2017. HeĀ is well versed in Hindi and English.

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