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Ashita Class 6 Tuition trainer in Raipur

Ashita

Tutor

Saddu, Raipur, India - 492014.

1 Student

Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

I have studying students Of CBSE board from last one year and being exposed n experienced best in science and maths. The rest of the subject like English, social studies, Hindi is not being difficult though.

Languages Spoken

Punjabi Mother Tongue (Native)

English Proficient

Hindi Basic

Education

Pt. Ravishankar university 2018

Bachelor of Science (B.Sc.)

Address

D12

Avinash suncity Daldal seoni near urkura road

Saddu, Raipur, India - 492014

Landmark: -daldal seoni

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Teaches

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

1

Board

ICSE, CBSE

CBSE Subjects taught

EVS, Punjabi, Social Science, English, Computers, Hindi, Science, Mathematics

ICSE Subjects taught

Physics, Mathematics, Punjabi, History, Geography, Chemistry, Computer Science, EVS, Biology, English

Taught in School or College

No

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

1

Board

ICSE, CBSE

CBSE Subjects taught

EVS, Punjabi, Social Science, English, Computers, Hindi, Science, Mathematics

ICSE Subjects taught

Physics, Mathematics, Punjabi, History, Geography, Chemistry, Computer Science, EVS, Biology, English

Taught in School or College

No

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

1

Board

ICSE, CBSE

CBSE Subjects taught

EVS, Punjabi, Social Science, English, Computers, Hindi, Science, Mathematics

ICSE Subjects taught

Physics, Mathematics, Punjabi, History, Geography, Chemistry, Computer Science, EVS, Biology, English

Taught in School or College

No

Hindi Language Classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Profession

Student

Outcomes taught for

Writing, Grammar and Vocabulary improvement, Reading, Hindi Speaking

Awards and Recognition

No

Mother Tongue

No

Languages apart from english in which classes are conducted

Yes

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

1

Board

CBSE, ICSE

CBSE Subjects taught

Hindi, Computers, Punjabi, Science, Mathematics, EVS, English

ICSE Subjects taught

Hindi, Punjabi, Science, Mathematics, EVS, Social Studies, English

Taught in School or College

No

Nursery-KG Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Nursery-KG Tuition

1

Subject

Mathematics, English, EVS

Taught in School or College

No

Teaching Experience in detail in Nursery-KG Tuition

Good speaking skills with good knowledge of subjects. Teaching students from 1-12.

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE

CBSE Subjects taught

Mathematics, Punjabi, English, Science, Information and Comunication Technology, Social science

Taught in School or College

No

Teaching Experience in detail in Class 10 Tuition

u

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE

CBSE Subjects taught

Mathematics, Punjabi, English, Science, Information and Comunication Technology, Social science

Taught in School or College

No

Teaching Experience in detail in Class 9 Tuition

u

Spoken English classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Age groups catered to

16 yrs to 25 yrs, Below 10 yrs, 10 yrs to 15 yrs

Lived or Worked in English Speaking Country

No

Exams Attended

IELTS

Awards and Recognition

No

Certification

None

Profession

Tutor

Language of instruction offered

English to English, Hindi to English

Curriculum Expertise

CBSE

Citizen of English Speaking Country

Yes

Class strength catered to

One on one/ Private Tutions, Group Classes

Teaching done in

Basic Spoken English, Vocabulary

Teaching at

Home

Gym

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Gym

1

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 8 do you teach for?

ICSE, CBSE

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach Class 10 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition, Class I-V Tuition, Gym, Hindi Language, Nursery-KG Tuition and Spoken English Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 1 year.

Answers by Ashita (8)

Answered on 08/08/2019 Learn Tuition

From the question we know (1,-2)i.e x=1 &y=-2 Putting the values of x and y in the equation 2x-3y=8 2*1-3*(-2)=8 (2*1=2 and 3*(-2)=-6) 2-(-6)=8 (-*-=+) 2+6=8 8=8 It proves that both sides are equal. Therefore ,(1,-2)is a solution of equation 2x-3y=8 ... ...more

From the question we know (1,-2)i.e x=1 &y=-2

Putting the values of x and y in the equation 

2x-3y=8

2*1-3*(-2)=8                  (2*1=2 and 3*(-2)=-6)

2-(-6)=8                          (-*-=+)

2+6=8

8=8

It proves that both sides are equal.   

Therefore ,(1,-2)is a solution of equation 2x-3y=8

       

Answers 294 Comments
Dislike Bookmark

Answered on 19/06/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3

Let the average speed of the passenger train be 'x' km/hr and the average speed of the express train be (x + 11) km/hrDistance between Mysore and Bangalore = 132 kmIt is given that the time taken by the express train to cover the distance of 132 km is 1 hour less than the passenger train to cover the... ...more

Let the average speed of the passenger train be 'x' km/hr and the average speed of the express train be (x + 11) km/hr
Distance between Mysore and Bangalore = 132 km
It is given that the time taken by the express train to cover the distance of 132 km is 1 hour less than the passenger train to cover the same distance.
So, time taken by passenger train = 132/x hr
The time taken by the express train = {(132)/x+11} hr
Now, according to the question
{132/(x+11)} = 132/x + 1
After taking L.C.M. of 132/x +1 and then solving it we get (132+x)/x.
Now,
{132/(x+11)} = (132+x)/x
By cross multiplying, we get
132x = x²+132x+11x+1452
x² + 11x - 1452 = 0
x² + 44x - 33x - 1452 = 0
x(x+44) - 33(x+44) = 0
(x+33) (x+44) = 0
x - 44 or x = 33
As the speed cannot be in negative therefore, x = 33 or the speed of the passenger train = 33 km/hr and the speed is 33 + 11 = 44 km/hr.

Answers 5 Comments
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Answered on 19/06/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3

The longest side of the triangles i.e. the hypotenuse.So, by Pythagoras Theorem,(Diagonal)² = (Smaller Side)² + (Longer Side)²(x + 60)² = (x)² + (x + 30)²x² + 120x + 3600 = x² + x² + 60x + 900x² + 60x - 120x + 900 - 3600 = 0x² - 60x - 2700 = 0x²... ...more

The longest side of the triangles i.e. the hypotenuse.
So, by Pythagoras Theorem,
(Diagonal)² = (Smaller Side)² + (Longer Side)²
(x + 60)² = (x)² + (x + 30)²
x² + 120x + 3600 = x² + x² + 60x + 900
x² + 60x - 120x + 900 - 3600 = 0
x² - 60x - 2700 = 0
x² - 90x + 30x - 2700 = 0
x(x - 90) + 30(x - 90) = 0
(x - 90) (x + 30) = 0
x = 90 because x = -30 as length cannot be possible.
So the length of the shorter side is 90 meters and the length of the longer side is 90 + 30 = 120 meters.

Answers 17 Comments
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Answered on 19/06/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3

Let the time taken by the smaller diameter tap = x larger = x-10 total time taken = 75 /8 portion filled in one hour by smaller diameter tap = 1/x and by larger diamter tap = 1/x-10 1/x + 1/x-10 = 8/75 x-10+x/x(x-10) = 8/75 2x+10/x²-10x = 8/75 8(x²-10x) = 75 ×2 (x-5) 8/2 (x²-10x)... ...more

Let the time taken by the smaller diameter tap = x

larger = x-10

total time taken = 75 /8

portion filled in one hour by smaller diameter tap = 1/x

and by larger diamter tap = 1/x-10

1/x + 1/x-10 = 8/75

x-10+x/x(x-10) = 8/75

2x+10/x²-10x = 8/75

8(x²-10x) = 75 ×2 (x-5)

8/2 (x²-10x) = 75 (x-5)

4x²-40x = 75x-375

4x² -40x-75x +375 = 0

4x²-115x + 375 = 0

4x²-100x-15x +375 = 0

4x(x-25)-15(x-25)=0

(x-25)(4x-15)

x= 25

x= 15/4

If x= 25 

the x-10 = 25-10 = 15

if x = 15/4

x-10 = 15/4 - 10 = 15-40/4 = -25/4

since time cannot be negative therefore x = 25.

Answers 7 Comments
Dislike Bookmark

Answered on 19/06/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.2

Let first number be x then second number be 27-x. According to question or Let us split middle term. Hence required numbers are 13 and 14. ...more

Let first number be x then second number be 27-x.

According to question
      
or 
Let us split middle term.
Hence required numbers are 13 and 14.
Answers 19 Comments
Dislike Bookmark

Teaches

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

1

Board

ICSE, CBSE

CBSE Subjects taught

EVS, Punjabi, Social Science, English, Computers, Hindi, Science, Mathematics

ICSE Subjects taught

Physics, Mathematics, Punjabi, History, Geography, Chemistry, Computer Science, EVS, Biology, English

Taught in School or College

No

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

1

Board

ICSE, CBSE

CBSE Subjects taught

EVS, Punjabi, Social Science, English, Computers, Hindi, Science, Mathematics

ICSE Subjects taught

Physics, Mathematics, Punjabi, History, Geography, Chemistry, Computer Science, EVS, Biology, English

Taught in School or College

No

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

1

Board

ICSE, CBSE

CBSE Subjects taught

EVS, Punjabi, Social Science, English, Computers, Hindi, Science, Mathematics

ICSE Subjects taught

Physics, Mathematics, Punjabi, History, Geography, Chemistry, Computer Science, EVS, Biology, English

Taught in School or College

No

Hindi Language Classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Profession

Student

Outcomes taught for

Writing, Grammar and Vocabulary improvement, Reading, Hindi Speaking

Awards and Recognition

No

Mother Tongue

No

Languages apart from english in which classes are conducted

Yes

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

1

Board

CBSE, ICSE

CBSE Subjects taught

Hindi, Computers, Punjabi, Science, Mathematics, EVS, English

ICSE Subjects taught

Hindi, Punjabi, Science, Mathematics, EVS, Social Studies, English

Taught in School or College

No

Nursery-KG Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Nursery-KG Tuition

1

Subject

Mathematics, English, EVS

Taught in School or College

No

Teaching Experience in detail in Nursery-KG Tuition

Good speaking skills with good knowledge of subjects. Teaching students from 1-12.

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE

CBSE Subjects taught

Mathematics, Punjabi, English, Science, Information and Comunication Technology, Social science

Taught in School or College

No

Teaching Experience in detail in Class 10 Tuition

u

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE

CBSE Subjects taught

Mathematics, Punjabi, English, Science, Information and Comunication Technology, Social science

Taught in School or College

No

Teaching Experience in detail in Class 9 Tuition

u

Spoken English classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Age groups catered to

16 yrs to 25 yrs, Below 10 yrs, 10 yrs to 15 yrs

Lived or Worked in English Speaking Country

No

Exams Attended

IELTS

Awards and Recognition

No

Certification

None

Profession

Tutor

Language of instruction offered

English to English, Hindi to English

Curriculum Expertise

CBSE

Citizen of English Speaking Country

Yes

Class strength catered to

One on one/ Private Tutions, Group Classes

Teaching done in

Basic Spoken English, Vocabulary

Teaching at

Home

Gym

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Gym

1

No Reviews yet!

Answers by Ashita (8)

Answered on 08/08/2019 Learn Tuition

From the question we know (1,-2)i.e x=1 &y=-2 Putting the values of x and y in the equation 2x-3y=8 2*1-3*(-2)=8 (2*1=2 and 3*(-2)=-6) 2-(-6)=8 (-*-=+) 2+6=8 8=8 It proves that both sides are equal. Therefore ,(1,-2)is a solution of equation 2x-3y=8 ... ...more

From the question we know (1,-2)i.e x=1 &y=-2

Putting the values of x and y in the equation 

2x-3y=8

2*1-3*(-2)=8                  (2*1=2 and 3*(-2)=-6)

2-(-6)=8                          (-*-=+)

2+6=8

8=8

It proves that both sides are equal.   

Therefore ,(1,-2)is a solution of equation 2x-3y=8

       

Answers 294 Comments
Dislike Bookmark

Answered on 19/06/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3

Let the average speed of the passenger train be 'x' km/hr and the average speed of the express train be (x + 11) km/hrDistance between Mysore and Bangalore = 132 kmIt is given that the time taken by the express train to cover the distance of 132 km is 1 hour less than the passenger train to cover the... ...more

Let the average speed of the passenger train be 'x' km/hr and the average speed of the express train be (x + 11) km/hr
Distance between Mysore and Bangalore = 132 km
It is given that the time taken by the express train to cover the distance of 132 km is 1 hour less than the passenger train to cover the same distance.
So, time taken by passenger train = 132/x hr
The time taken by the express train = {(132)/x+11} hr
Now, according to the question
{132/(x+11)} = 132/x + 1
After taking L.C.M. of 132/x +1 and then solving it we get (132+x)/x.
Now,
{132/(x+11)} = (132+x)/x
By cross multiplying, we get
132x = x²+132x+11x+1452
x² + 11x - 1452 = 0
x² + 44x - 33x - 1452 = 0
x(x+44) - 33(x+44) = 0
(x+33) (x+44) = 0
x - 44 or x = 33
As the speed cannot be in negative therefore, x = 33 or the speed of the passenger train = 33 km/hr and the speed is 33 + 11 = 44 km/hr.

Answers 5 Comments
Dislike Bookmark

Answered on 19/06/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3

The longest side of the triangles i.e. the hypotenuse.So, by Pythagoras Theorem,(Diagonal)² = (Smaller Side)² + (Longer Side)²(x + 60)² = (x)² + (x + 30)²x² + 120x + 3600 = x² + x² + 60x + 900x² + 60x - 120x + 900 - 3600 = 0x² - 60x - 2700 = 0x²... ...more

The longest side of the triangles i.e. the hypotenuse.
So, by Pythagoras Theorem,
(Diagonal)² = (Smaller Side)² + (Longer Side)²
(x + 60)² = (x)² + (x + 30)²
x² + 120x + 3600 = x² + x² + 60x + 900
x² + 60x - 120x + 900 - 3600 = 0
x² - 60x - 2700 = 0
x² - 90x + 30x - 2700 = 0
x(x - 90) + 30(x - 90) = 0
(x - 90) (x + 30) = 0
x = 90 because x = -30 as length cannot be possible.
So the length of the shorter side is 90 meters and the length of the longer side is 90 + 30 = 120 meters.

Answers 17 Comments
Dislike Bookmark

Answered on 19/06/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3

Let the time taken by the smaller diameter tap = x larger = x-10 total time taken = 75 /8 portion filled in one hour by smaller diameter tap = 1/x and by larger diamter tap = 1/x-10 1/x + 1/x-10 = 8/75 x-10+x/x(x-10) = 8/75 2x+10/x²-10x = 8/75 8(x²-10x) = 75 ×2 (x-5) 8/2 (x²-10x)... ...more

Let the time taken by the smaller diameter tap = x

larger = x-10

total time taken = 75 /8

portion filled in one hour by smaller diameter tap = 1/x

and by larger diamter tap = 1/x-10

1/x + 1/x-10 = 8/75

x-10+x/x(x-10) = 8/75

2x+10/x²-10x = 8/75

8(x²-10x) = 75 ×2 (x-5)

8/2 (x²-10x) = 75 (x-5)

4x²-40x = 75x-375

4x² -40x-75x +375 = 0

4x²-115x + 375 = 0

4x²-100x-15x +375 = 0

4x(x-25)-15(x-25)=0

(x-25)(4x-15)

x= 25

x= 15/4

If x= 25 

the x-10 = 25-10 = 15

if x = 15/4

x-10 = 15/4 - 10 = 15-40/4 = -25/4

since time cannot be negative therefore x = 25.

Answers 7 Comments
Dislike Bookmark

Answered on 19/06/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.2

Let first number be x then second number be 27-x. According to question or Let us split middle term. Hence required numbers are 13 and 14. ...more

Let first number be x then second number be 27-x.

According to question
      
or 
Let us split middle term.
Hence required numbers are 13 and 14.
Answers 19 Comments
Dislike Bookmark

Contact

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Ashita describes herself as Tutor. She conducts classes in Class 10 Tuition, Class 6 Tuition and Class 7 Tuition. Ashita is located in Saddu, Raipur. Ashita takes at students Home and Regular Classes- at her Home. She has 1 years of teaching experience . Ashita has completed Bachelor of Science (B.Sc.) from Pt. Ravishankar university in 2018. She is well versed in Hindi, English and Punjabi.

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