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Rajagopalan Nair

Physics and Maths made easy

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Overview

- I have passed M.Sc in Physics from University of Kerala.
- Qualified as CSIR (Council of Scientific and Industrial
Research )
- I have taught Physics in the graduate level in National
Defence Academy Pune for 18 years
- Taught Physics at the Post Graduate level in Y M College
, Pune
- Taught Physics at the graduate level in PICT, Pune
In my opinion, a student has to be trained to gather knowledge from various sources including books and recent multimedia. A teacher is just a guide. With so many false rumors on the rise, it is likely for a fragile mind to succumb to them. Developing the discriminatory power in him/her against reality and hype is very crucial.The competitions have forced these students to have a wrong outlook towards learning, i.e., mug up comes first, and understanding is just secondary. He must learn to apply and put to use every new concept he learns and not just produce it in paper work. Visual aids make learning more fun and I make Power Point presentations as such aids.

Languages Spoken

English

Malayalam

Education

University of Kerala 1986

Master of Science (M.Sc.)

Address

Camp, Pune, India - 411001

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Online (video chat via skype, google hangout etc)

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Class 11 Tuition

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Class 12 Tuition

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MSc Tuition

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Answers by Rajagopalan Nair (69)

Answered on 19/02/2015 Learn Tuition/Class XI-XII Tuition (PUC)

When the internal resistance is zero. If otherwise, the voltage across the terminals of the source suffers a loss across the internal resistance of the emf source.
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Answered on 19/02/2015 Learn Tuition/Class XI-XII Tuition (PUC)

Electromotive force is basically a potential difference (time dependent or time independent) and is expressed in SI units as Volts. Therefore it dimensionally matches to express it as E=W/q where W is the work done(expressed in Joules) in moving a particle of charge between two points in question (across... ...more
Electromotive force is basically a potential difference (time dependent or time independent) and is expressed in SI units as Volts. Therefore it dimensionally matches to express it as E=W/q where W is the work done(expressed in Joules) in moving a particle of charge between two points in question (across which electromotive force has to be evaluated). This suits (for example) as across the +ve and -ve terminals of a cell/battery, through a conducting path of high enough resistance that the charge stored at the mentioned +ve and -ve terminals don't drop considerably with the effect of the conducting path (as the path is a device draining away the charges accumulated at the mentioned +ve and -ve terminals). This is exactly what is done when one measures the emf across a battery (or any other source of electrical current) with a voltmeter. However, the emf is also generated by what is called displacement current (discovered by J C Maxwell) which was instrumental at unifying electric field with magnetic field. In this case there is a net flow of charge from one terminal to the other, but, an oscillation of dipole moments. The phenomenon becomes visible at extremely high frequencies of oscillation. In this case the emf is time dependent.
Answers 31 Comments
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Answered on 15/02/2015 Learn Tuition/Class XI-XII Tuition (PUC)

For your knowledge, at the very fundamental level there is a difference that optical light microscopy involves optical lenses using refraction, a wave property and electron microscope makes use of electrostatic lenses which makes use of deflection of individual electrons in an electron beam as individual,... ...more
For your knowledge, at the very fundamental level there is a difference that optical light microscopy involves optical lenses using refraction, a wave property and electron microscope makes use of electrostatic lenses which makes use of deflection of individual electrons in an electron beam as individual, classical particles. If photon picture used to explain optical microscope's action, we say the uncertainty principle applied to each photon helps focusing of each photon!
Answers 7 Comments
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Answered on 15/02/2015 Learn Tuition/Class XI-XII Tuition (PUC)

Write 1.0 = 1.0* Therefore (1.0)^(1/3) = 1.0 * for n={0,1,2} Therefore the cube roots are 1.0, (1/2) + i*sq root (3))/2, (-1/2)+ i*(- sq root (3))/2] sum of which three roots is + i * = 0+i*0 ...more
Write 1.0 = 1.0*[cos(2*n*pi) + sin(2*n*pi)] Therefore (1.0)^(1/3) = 1.0 * [cos(2*n*pi/3)+sin(2*n*pi/3)] for n={0,1,2} Therefore the cube roots are 1.0, (1/2) + i*sq root (3))/2, (-1/2)+ i*(- sq root (3))/2] sum of which three roots is [1+(1/2)+(-1/2)] + i * [(sq root (3))/2 - (sq root (3))/2] = 0+i*0
Answers 7 Comments
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MSc Tuition

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Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

BSc Tuition

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Online (video chat via skype, google hangout etc)

Student's Home

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Class 11 Tuition

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Online (video chat via skype, google hangout etc)

Student's Home

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Class 12 Tuition

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Student's Home

Tutor's Home

No Reviews yet!

Answers by Rajagopalan Nair (69)

Answered on 19/02/2015 Learn Tuition/Class XI-XII Tuition (PUC)

When the internal resistance is zero. If otherwise, the voltage across the terminals of the source suffers a loss across the internal resistance of the emf source.
Answers 11 Comments
Dislike Bookmark

Answered on 19/02/2015 Learn Tuition/Class XI-XII Tuition (PUC)

Electromotive force is basically a potential difference (time dependent or time independent) and is expressed in SI units as Volts. Therefore it dimensionally matches to express it as E=W/q where W is the work done(expressed in Joules) in moving a particle of charge between two points in question (across... ...more
Electromotive force is basically a potential difference (time dependent or time independent) and is expressed in SI units as Volts. Therefore it dimensionally matches to express it as E=W/q where W is the work done(expressed in Joules) in moving a particle of charge between two points in question (across which electromotive force has to be evaluated). This suits (for example) as across the +ve and -ve terminals of a cell/battery, through a conducting path of high enough resistance that the charge stored at the mentioned +ve and -ve terminals don't drop considerably with the effect of the conducting path (as the path is a device draining away the charges accumulated at the mentioned +ve and -ve terminals). This is exactly what is done when one measures the emf across a battery (or any other source of electrical current) with a voltmeter. However, the emf is also generated by what is called displacement current (discovered by J C Maxwell) which was instrumental at unifying electric field with magnetic field. In this case there is a net flow of charge from one terminal to the other, but, an oscillation of dipole moments. The phenomenon becomes visible at extremely high frequencies of oscillation. In this case the emf is time dependent.
Answers 31 Comments
Dislike Bookmark

Answered on 15/02/2015 Learn Tuition/Class XI-XII Tuition (PUC)

For your knowledge, at the very fundamental level there is a difference that optical light microscopy involves optical lenses using refraction, a wave property and electron microscope makes use of electrostatic lenses which makes use of deflection of individual electrons in an electron beam as individual,... ...more
For your knowledge, at the very fundamental level there is a difference that optical light microscopy involves optical lenses using refraction, a wave property and electron microscope makes use of electrostatic lenses which makes use of deflection of individual electrons in an electron beam as individual, classical particles. If photon picture used to explain optical microscope's action, we say the uncertainty principle applied to each photon helps focusing of each photon!
Answers 7 Comments
Dislike Bookmark

Answered on 15/02/2015 Learn Tuition/Class XI-XII Tuition (PUC)

Write 1.0 = 1.0* Therefore (1.0)^(1/3) = 1.0 * for n={0,1,2} Therefore the cube roots are 1.0, (1/2) + i*sq root (3))/2, (-1/2)+ i*(- sq root (3))/2] sum of which three roots is + i * = 0+i*0 ...more
Write 1.0 = 1.0*[cos(2*n*pi) + sin(2*n*pi)] Therefore (1.0)^(1/3) = 1.0 * [cos(2*n*pi/3)+sin(2*n*pi/3)] for n={0,1,2} Therefore the cube roots are 1.0, (1/2) + i*sq root (3))/2, (-1/2)+ i*(- sq root (3))/2] sum of which three roots is [1+(1/2)+(-1/2)] + i * [(sq root (3))/2 - (sq root (3))/2] = 0+i*0
Answers 7 Comments
Dislike Bookmark
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Rajagopalan Nair describes himself as Physics and Maths made easy. He conducts classes in BSc Tuition, Class 11 Tuition and Class 12 Tuition. Rajagopalan is located in Camp, Pune. Rajagopalan takes Online Classes- via online medium. He has 20 years of teaching experience . Rajagopalan has completed Master of Science (M.Sc.) from University of Kerala in 1986. HeĀ is well versed in English and Malayalam.

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