UrbanPro
true
Atharv Aundhekar NTSE exam trainer in Nanded

Atharv Aundhekar

Tutor

Ashoknagar, Nanded, India - 431605.

Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

Details verified of Atharv Aundhekar

Identity

Education

Know how UrbanPro verifies Tutor details

Identity is verified based on matching the details uploaded by the Tutor with government databases.

Overview

I am a B.Tech student who has command on maths,mental ability and willing to teach. I will help you to get easy in mathematics and metal ability.

Languages Spoken

Hindi

English

Marathi

Education

SGGSIE&T, NANDED Pursuing

Bachelor of Technology (B.Tech.)

Address

Ashoknagar, Nanded, India - 431605

Verified Info

Phone Verified

Email Verified

Report this Profile

Is this listing inaccurate or duplicate? Any other problem?

Please tell us about the problem and we will fix it.

Please describe the problem that you see in this page.

Type the letters as shown below *

Please enter the letters as show below

Teaches

NTSE exam Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, State

CBSE Subjects taught

Mathematics, Marathi, Science

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Social Science, English, Marathi, Science

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, State

CBSE Subjects taught

Mathematics, Marathi, Science

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Social Science, English, Marathi, Science

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

Mathematics, Marathi, English, Science

Taught in School or College

No

State Syllabus Subjects taught

Marathi, English, Mathematics, Science

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

Mathematics, Marathi, English, Science

Taught in School or College

No

State Syllabus Subjects taught

Marathi, English, Mathematics, Science

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

Mathematics, Marathi, English, Science

Taught in School or College

No

State Syllabus Subjects taught

Marathi, English, Mathematics, Science

National Scholarship Exam(NSE) Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Math Olympiad classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Science Olympiad classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Reviews

No Reviews yet! Be the first one to Review

FAQs

1. Which classes do you teach?

I teach Class 10 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition, Math Olympiad, NTSE exam Coaching, National Scholarship Exam(NSE) Coaching and Science Olympiad Classes.

2. Do you provide a demo class?

Yes, I provide a free demo class.

3. How many years of experience do you have?

I have been teaching for less than a year.

Answers by Atharv Aundhekar (5)

Answered on 08/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

Mean of 100 observation=50 So total sum =50×100=5000 Now one observation is replaced having value 50 by 150 So change in sum=150-50=100 Therefore change in sum=100 So new sum is 5100 Therefore new mean is 5100/100=51
Answers 49 Comments
Dislike Bookmark

Answered on 08/12/2017 Learn CBSE/Class 10/Science +1 Tuition/Class IX-X Tuition

R=resistivity*lenghth/area So resistivity=R×A/L Therefore resistivity=5.026×10^-6
Answers 6 Comments
Dislike Bookmark

Answered on 05/12/2017 Learn CBSE/Class 9/Science +1 Tuition/Class IX-X Tuition

Molecular mass of O=16 and H=2 so molecular mass of H2O=18
Answers 25 Comments
Dislike Bookmark

Answered on 05/12/2017 Learn CBSE/Class 10/Science +1 Tuition/Class IX-X Tuition

Potential difference is simply the level difference between two points. In the case of charge it is measured in volts
Answers 21 Comments
Dislike Bookmark

Answered on 04/12/2017 Learn Tuition/Class IX-X Tuition

Newton's second law is simply stated as F=ma where F is the force applied m is the mass and a is acceleration
Answers 206 Comments
Dislike Bookmark

Teaches

NTSE exam Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, State

CBSE Subjects taught

Mathematics, Marathi, Science

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Social Science, English, Marathi, Science

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, State

CBSE Subjects taught

Mathematics, Marathi, Science

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Social Science, English, Marathi, Science

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

Mathematics, Marathi, English, Science

Taught in School or College

No

State Syllabus Subjects taught

Marathi, English, Mathematics, Science

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

Mathematics, Marathi, English, Science

Taught in School or College

No

State Syllabus Subjects taught

Marathi, English, Mathematics, Science

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

Mathematics, Marathi, English, Science

Taught in School or College

No

State Syllabus Subjects taught

Marathi, English, Mathematics, Science

National Scholarship Exam(NSE) Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Math Olympiad classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Science Olympiad classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

No Reviews yet! Be the first one to Review

Answers by Atharv Aundhekar (5)

Answered on 08/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

Mean of 100 observation=50 So total sum =50×100=5000 Now one observation is replaced having value 50 by 150 So change in sum=150-50=100 Therefore change in sum=100 So new sum is 5100 Therefore new mean is 5100/100=51
Answers 49 Comments
Dislike Bookmark

Answered on 08/12/2017 Learn CBSE/Class 10/Science +1 Tuition/Class IX-X Tuition

R=resistivity*lenghth/area So resistivity=R×A/L Therefore resistivity=5.026×10^-6
Answers 6 Comments
Dislike Bookmark

Answered on 05/12/2017 Learn CBSE/Class 9/Science +1 Tuition/Class IX-X Tuition

Molecular mass of O=16 and H=2 so molecular mass of H2O=18
Answers 25 Comments
Dislike Bookmark

Answered on 05/12/2017 Learn CBSE/Class 10/Science +1 Tuition/Class IX-X Tuition

Potential difference is simply the level difference between two points. In the case of charge it is measured in volts
Answers 21 Comments
Dislike Bookmark

Answered on 04/12/2017 Learn Tuition/Class IX-X Tuition

Newton's second law is simply stated as F=ma where F is the force applied m is the mass and a is acceleration
Answers 206 Comments
Dislike Bookmark

Atharv Aundhekar describes himself as Tutor. He conducts classes in Class 10 Tuition, Class 6 Tuition and Class 7 Tuition. Atharv is located in Ashoknagar, Nanded. Atharv takes Regular Classes- at his Home. Atharv is pursuing Bachelor of Technology (B.Tech.) from SGGSIE&T,NANDED. He is well versed in Hindi, English and Marathi.

X

Reply to 's review

Enter your reply*

1500/1500

Please enter your reply

Your reply should contain a minimum of 10 characters

Your reply has been successfully submitted.

Certified

The Certified badge indicates that the Tutor has received good amount of positive feedback from Students.

Different batches available for this Course

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more