# Sumesh P

Kalyanagiri, Mysore, India- 570019.

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## Overview

10 years of teaching experience in higher secondary and engineering college.
Strong foundation in basic concepts in Physics and Mathematics
Excellent problem solving skill.
Ability to explain tough problems in lucid language.
Expert in usage of multimedia to build innovative teaching methodology.

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## Education

Master of Science (M.Sc.) from Annamalai University in 2006.

Kalyanagiri, Mysore, India- 570019.

## Class 11 Tuition Overview

Class 11 Tuition

Board

ISC/ICSE, State, CBSE

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

Taught in School or College

Yes

State Syllabus Subjects taught

Physics

Class Location

Online (video chat via skype, google hangout etc)

Years of Experience in Class 11 Tuition

10

## Reviews

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## Answers by Sumesh P (1)

"On a straight road, if a car is moving with the speed of 180 kmh-1 and the driver stops the car in 25 s by applying brakes, then determine the distance covered by the car during the time brakes are applied. Assume, acceleration of the car be uniform throughout the retarding motion." in

$S=ut+\frac{1}{2}at^{2}$

Speed of the car =180km/h = $\frac{180*10^{3}m}{3600s}=5m/s$

When the driver applies Break, the speed of the car is 5m/s. So that we can take initial speed 'u' as 5m/s. When the car stops after 25 seconds, the final speed is 0 m/s = ??.

Then, the distance travelled can be calculated from the above formula. Where,

$a&space;=&space;\frac{0-5}{25}$

Therefore, $S&space;=&space;5*25+\frac{1}{2}(-0.2)(25)^{2}$

$S=125-62.5&space;=&space;62.5&space;meter$

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Class 11 Tuition

Board

ISC/ICSE, State, CBSE

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

Taught in School or College

Yes

State Syllabus Subjects taught

Physics

Class Location

Online (video chat via skype, google hangout etc)

Years of Experience in Class 11 Tuition

10

Class 12 Tuition

Board

ISC/ICSE, State, CBSE

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

Taught in School or College

Yes

State Syllabus Subjects taught

Physics

Class Location

Online (video chat via skype, google hangout etc)

Years of Experience in Class 12 Tuition

10

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No Reviews yet! Be the first one to Review

"On a straight road, if a car is moving with the speed of 180 kmh-1 and the driver stops the car in 25 s by applying brakes, then determine the distance covered by the car during the time brakes are applied. Assume, acceleration of the car be uniform throughout the retarding motion." in

$S=ut+\frac{1}{2}at^{2}$

Speed of the car =180km/h = $\frac{180*10^{3}m}{3600s}=5m/s$

When the driver applies Break, the speed of the car is 5m/s. So that we can take initial speed 'u' as 5m/s. When the car stops after 25 seconds, the final speed is 0 m/s = ??.

Then, the distance travelled can be calculated from the above formula. Where,

$a&space;=&space;\frac{0-5}{25}$

Therefore, $S&space;=&space;5*25+\frac{1}{2}(-0.2)(25)^{2}$

$S=125-62.5&space;=&space;62.5&space;meter$

0
|
0

Sumesh P conducts classes in Class 11 Tuition and Class 12 Tuition. Sumesh is located in Kalyanagiri, Mysore. Sumesh takes Online Classes- via online medium. He has 10 years of teaching experience . Sumesh has completed Master of Science (M.Sc.) from Annamalai University in 2006. HeĀ is well versed in Tamil, Hindi, Malayalam, Kannada and English.

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