Ashish Kumar

Chembur East, Mumbai, India - 400074

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Ashish Kumar

Chembur East, Mumbai, India - 400074.

3.4

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Overview

I am a lecturer in Physics department in FIITJEE Limited. I have been teaching for more than 2 years. I have a degree in Civil Engineering.

Languages Spoken

Hindi Mother Tongue (Native)

English Basic

Education

UPTU 2015

Bachelor of Technology (B.Tech.)

Address

Chembur East, Mumbai, India - 400074

Verified Info

Phone Verified

Email Verified

Demo Class

No

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Engineering Entrance Coaching classes Overview

Engineering Entrance Coaching classes

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Engineering Entrance Coaching classes

3

Engineering Entrance Exams

IIT JEE Coaching Classes

IITJEE Coaching

IIT JEE Integrated Coaching, IIT JEE Foundation Course, IIT JEE Advanced Coaching, IIT JEE Crash Course, IIT JEE Mains Coaching

Type of class

Regular Classes, Crash Course

IIT-JEE Subjects

Physics

Reviews

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FAQs

1. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 9 Tuition and Engineering Entrance Coaching Classes.

2. Do you provide a demo class?

No, I don't provide a demo class.

3. How many years of experience do you have?

I have been teaching for 3 years.

Answers by Ashish Kumar (2)

Answered on 25 Jun Tuition

x³ + y³ + z³ - 3xyz = (x + y + z) (x² + y² + z² - xy - yz - zx) since we have x² + y² + z² = xy + yz + zx x³ + y³ + z³ - 3xyz = 0 ... ...more

x³ + y³ + z³ - 3xyz = (x + y + z) (x² + y² + z² - xy - yz - zx)                                                                                     

since we have x² + y² + z² = xy + yz + zx                    

x³ + y³ + z³ - 3xyz = 0                                                     

x³ + y³ + z³ = 3xyz

Answers 276 Comments
Dislike Bookmark

Answered on 25 Jun Tuition

x³ + y³ + z³ - 3xyz = (x + y + z) (x² + y² + z² - xy - yz - zx) since we have x² + y² + z² = xy + yz + zx x³ + y³ + z³ - 3xyz = 0 x³ + y³ + z³ = 3xyz
Answers 276 Comments
Dislike Bookmark

Ashish KumarDirections

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Engineering Entrance Coaching classes 3.4

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Engineering Entrance Coaching classes

3

Engineering Entrance Exams

IIT JEE Coaching Classes

IITJEE Coaching

IIT JEE Integrated Coaching, IIT JEE Foundation Course, IIT JEE Advanced Coaching, IIT JEE Crash Course, IIT JEE Mains Coaching

Type of class

Regular Classes, Crash Course

IIT-JEE Subjects

Physics

Class 12 Tuition 3.4

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 12 Tuition

3

Board

State, ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

Taught in School or College

No

State Syllabus Subjects taught

Physics

Class 11 Tuition 3.4

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 11 Tuition

3

Board

State, ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

Taught in School or College

No

State Syllabus Subjects taught

Physics

Class 10 Tuition 3.4

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 10 Tuition

3

Board

ICSE, State, CBSE

CBSE Subjects taught

Science

ICSE Subjects taught

Physics

Taught in School or College

No

State Syllabus Subjects taught

Science

Class 9 Tuition 3.4

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 9 Tuition

3

Board

ICSE, State, CBSE

CBSE Subjects taught

Science

ICSE Subjects taught

Physics

Experience in School or College

I have teached in Engineering Colleges.

Taught in School or College

Yes

State Syllabus Subjects taught

Science

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No Reviews yet! Be the first one to Review

Answers by Ashish Kumar (2)

Answered on 25 Jun Tuition

x³ + y³ + z³ - 3xyz = (x + y + z) (x² + y² + z² - xy - yz - zx) since we have x² + y² + z² = xy + yz + zx x³ + y³ + z³ - 3xyz = 0 ... ...more

x³ + y³ + z³ - 3xyz = (x + y + z) (x² + y² + z² - xy - yz - zx)                                                                                     

since we have x² + y² + z² = xy + yz + zx                    

x³ + y³ + z³ - 3xyz = 0                                                     

x³ + y³ + z³ = 3xyz

Answers 276 Comments
Dislike Bookmark

Answered on 25 Jun Tuition

x³ + y³ + z³ - 3xyz = (x + y + z) (x² + y² + z² - xy - yz - zx) since we have x² + y² + z² = xy + yz + zx x³ + y³ + z³ - 3xyz = 0 x³ + y³ + z³ = 3xyz
Answers 276 Comments
Dislike Bookmark

Ashish Kumar conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Ashish is located in Chembur East, Mumbai. Ashish takes at students Home. He has 3 years of teaching experience . Ashish has completed Bachelor of Technology (B.Tech.) from UPTU in 2015. HeĀ is well versed in Hindi and English.

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