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Jasmin 28/10/2016 in  Class XI-XII Tuition (PUC), Mathematics(Class XI-XII Tuition (PUC)), Straight Line

Find the equation of one of the sides of an isosceles right angled triangle whose hypotenuse is given by 3x + 4y = 4 and the opposite vertex of the hypotenuse is (2, 2)?

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Suresh 28/10/2016 in  Class XI-XII Tuition (PUC), Mathematics(Class XI-XII Tuition (PUC)), Straight Line

If the equation of the base of an equilateral triangle is x + y = 2 and the vertex is (2, -1), then find the length of the side of the triangle?

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M

Meenakshisundarams 28/10/2016 in  Class XI-XII Tuition (PUC), Mathematics(Class XI-XII Tuition (PUC)), Straight Line

In what direction should a line be drawn through the point (1, 2) so that its point of intersection with the line x + y = 4 is at a distance (square root of 6)/3 from the given point?

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K

Kiran 28/10/2016 in  Class XI-XII Tuition (PUC), Mathematics(Class XI-XII Tuition (PUC)), Straight Line

Find the equation of the lines which passes through the point (-4, 3) and the portion of the line intercepted between the axes is divided internally in the ratio 5:3 by this point?

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A

Anu 28/10/2016 in  Class XI-XII Tuition (PUC), Mathematics(Class XI-XII Tuition (PUC)), Straight Line

Find the equation of the lines through the point of intersection of the lines x - y + 1 = 0 and 2x - 3y + 5 =0 and whose distance from the point (3, 2) is 7/5?

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S

Sounak 28/10/2016 in  Class XI-XII Tuition (PUC), Mathematics(Class XI-XII Tuition (PUC)), Straight Line

If the sum of the distance of a moving point in a plane from the axes is 1, then find the locus of the point?

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D

Deep 28/10/2016 in  Class XI-XII Tuition (PUC), Mathematics(Class XI-XII Tuition (PUC)), Straight Line

What is the equation of the line if the line cutting off intercept -3 from the y-axis and the tangent at angle to the x-axis is 3/5?

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A

Ann 28/10/2016 in  Class XI-XII Tuition (PUC), Mathematics(Class XI-XII Tuition (PUC)), Straight Line

What is the slope of a line which cuts off intercepts of equal lengths on the axes?

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A

Apoorva 28/10/2016 in  Class XI-XII Tuition (PUC), Mathematics(Class XI-XII Tuition (PUC)), Straight Line

What is the equation of a line passing through the point (1, 2) and perpendicular to the line x + y + 1 = 0?

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M

Millennium 28/10/2016 in  Class XI-XII Tuition (PUC), Mathematics(Class XI-XII Tuition (PUC)), Straight Line

What is the value of the point (a, b) if the line x/a + y/b = 1 passes through the points (2, -3) and (4, -5)?

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A

Anitha 28/10/2016 in  Class XI-XII Tuition (PUC), Mathematics(Class XI-XII Tuition (PUC)), Straight Line

What is the equation of lines which passes through the point (3, -2) and are inclined at 60 degree to the line (square root of 3) x + y = 1?

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K

Kasireddy 28/10/2016 in  Class XI-XII Tuition (PUC), Mathematics(Class XI-XII Tuition (PUC)), Straight Line

What is the distance between the lines: y = mx + c1 and y = mx + c2?

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S

Sandeep 28/10/2016 in  Class XI-XII Tuition (PUC), Mathematics(Class XI-XII Tuition (PUC)), Straight Line

What is the coordinate point of the foot of perpendiculars from the point (2, 3) on the line y = 3x + 4?

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V

Vijay 28/10/2016 in  Class XI-XII Tuition (PUC), Mathematics(Class XI-XII Tuition (PUC)), Straight Line

What is the equation of a line passing through (1, 2) and parallel to the line y = 3x - 1?

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D

Debojyoti 28/10/2016 in  Class XI-XII Tuition (PUC), Mathematics(Class XI-XII Tuition (PUC)), Straight Line

What is the equation of diagonals of the square formed by the lines x= 0, y = 0, x = 1 and y =1?

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A

Archit 10/10/2016 in  Class XI-XII Tuition (PUC), Mathematics(Class XI-XII Tuition (PUC))

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Kunalthakur replied | 09/11/2016

contemplate on basic

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Kunalthakur replied | 09/11/2016

go to basic

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N

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Kanwar Kanishk Thakur replied | 11/11/2016

The word FRIDAY has six letters, therefore total words that can be formed = 6! = 720

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Sarvajeet replied | 06/12/2016

6! = 720.

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C

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Johnson replied | 24/10/2016

5!/2!= 60

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Sarvajeet replied | 06/12/2016

5!/2!= 60.

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H

Hamdaan 30/09/2016 in  Permutations, Class XI-XII Tuition (PUC), Mathematics(Class XI-XII Tuition (PUC))

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Prateek replied | 29/10/2016

120

0 0

Sarvajeet replied | 06/12/2016

120.

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A

Arunsundar 30/09/2016 in  Permutations, Class XI-XII Tuition (PUC), Mathematics(Class XI-XII Tuition (PUC))

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Sarvajeet replied | 06/12/2016

5040.

0 0

Ravi Ranjan replied | 07 Jan

7!

0 0

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A

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Santosh replied | 14/10/2016

The sum of all the digits = 0+1+2+3+4+5+6 = 21
Hance any six digit number created with these digit is divisible by 3.
At the leftmost position '0' can not be there.
So total six digits numbers without repeatation of digits :
6 × 6 × 5 × 4 × 3 × 2 = 4320
If repeatation is allowed than this question become more complicated and complexity will be more then the time :-)

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A

Arun Sharma replied | 15/10/2016

Please ignore my previous answer .

Answer is 1920

The number of digits possible with 1,2,3,4,5 and 6 = 6X5X4X3X2X1 = 720

The number of digits possible with 0,1,2,3,4 and 5 = 5X5X4X3X2X1 = 600

The number of digits possible with 0,1,2,4,5 and 6 = 5X5X4X3X2X1 = 600

Total numbers = 720 +600+600 = 1920

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F

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Hanuman replied | 21/10/2016

11*10*11=1210

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Debojyoti Roy replied | 23/10/2016

Captain can be selected in 11 C 1 ways. after selecting Captain ,Vicecaptain can be selested in 10 C 1 ways and afterth is Wicket Keeper can be selected in 9 C 1 ways.
Therefore required no. Of ways= 11C1 * 10C1 * 9C1
=11 * 10 * 9

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V

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Durgesh replied | 12/10/2016

7C3*5C5
=( 7!/3!*(7-3)! ) / 1
= 7*6*5*4! /3!*4!
= 7*5 =35

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Anish replied | 20/10/2016

7C3*5C5=35

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V

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Debojyoti Roy replied | 23/10/2016

Out of 12 consonants 6 consonants can be chosen in 12C6 ways. Out of 4 vowels 3 can be chosen in 4C3 ways. And all these 9 letters can arrange among themselves in 9! Ways.
So required no. Of ways= 12C6 * 4C3 * 9!

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R

Ritu replied | 24/10/2016

Number of ways to select 6 consonants from 12
= 12C6
Number of ways to select 3 vowels from 4
= 4C3

Number of ways of selecting 6 consonants from 12 and 3 vowels from 4
= 12C6 4C3
=(12!/((12-6)!*6!)) (4!/((4-3)!*4!))
=(12!/(6!*6!) (4!/(1!*4!))
=3696
It means we can have 3696 groups where each group contains total 9 letters (6...  more»
Number of ways to select 6 consonants from 12
= 12C6
Number of ways to select 3 vowels from 4
= 4C3

Number of ways of selecting 6 consonants from 12 and 3 vowels from 4
= 12C6 × 4C3
=(12!/((12-6)!*6!)) ×(4!/((4-3)!*4!))
=(12!/(6!*6!) ×(4!/(1!*4!))
=3696
It means we can have 3696 groups where each group contains total 9 letters (6 consonants and 3 vowels).

Number of ways to arrange 9 letters among themselves
=9!

Hence, required number of ways
=3696×9! «less

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R

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Prateek replied | 29/10/2016

35

0 0
S

Sukhada replied | 14/11/2016

35

0 0

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