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Vikash P. Class 11 Tuition trainer in Kolkata

Vikash P.

An Engineer

Bansdroni, Kolkata, India - 700070.

Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

Teaching Mathematics from last 3 years, providing the true concept and knowledge of Mathematics in an interesting approach.

Languages Spoken

English

Hindi

Education

FIEM Pursuing

Bachelor of Technology (B.Tech.)

KHAN ACADEMY 2018

SUMMER TEACHER CERTIFICATE

Address

37A, Adiganga Road

Bansdroni

Bansdroni, Kolkata, India - 700070

Landmark: Masterda Surya Sen Metro Station

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Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

5

Board

State, CBSE, ISC/ICSE

ISC/ICSE Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

5

Board

State, CBSE, ISC/ICSE

ISC/ICSE Subjects taught

Mathematics

CBSE Subjects taught

Physics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

5

Board

State, CBSE, ICSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

BCom Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BCom Tuition

3

BCom Subject

Business Mathematics and Statistics

Type of class

Regular Classes, Crash Course

Class strength catered to

Group Classes

Taught in School or College

No

Documents (4)

ICSE Mock Test for standard 10

ICSE 2nd MockTest for stndrd X

3rd year BCOM Mock Test CU

3rd yr BCOM Mock Test paper

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 12 do you teach for?

State, CBSE and ISC/ICSE

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach BCom Tuition, Class 10 Tuition, Class 11 Tuition and Class 12 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 5 years.

Answers by Vikash P. (10)

Answered on 19/06/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3

According to the problem statement: ________(i) ________(ii) Putting the value of in equation (i) we get ...more

According to the problem statement: ________(i)

________(ii)

Putting the value of  in equation (i) we get 

Answers 13 Comments
Dislike Bookmark

Answered on 19/06/2019 Learn CBSE/Class 9 +1 CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/ Class 10 Situational problems based on quadratic equations.

Use the sum of AP series concept, where Sn= 66, first term a1=1, common difference d=1, then find n. Putting all the values in the formula of Sn we get, n^2+n-132=0 Required answer= n+1 which will come to be 12 (OPTION B)
Answers 3 Comments
Dislike Bookmark

Answered on 19/06/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3

Let Mathematics marks be x and that of English be y, Solve the following equations: x+y=30____(i) (x+2)(y-3)=210___(ii) In equtation (ii) substitute y in terms of x using equation (i), then we get (x+2)(27-x)=210 solving the above quadration equation two possible... ...more

Let Mathematics marks be x and that of English be y,

Solve the following equations: x+y=30____(i)

                                            (x+2)(y-3)=210___(ii)

In equtation (ii) substitute y in terms of x using equation (i), then we get (x+2)(27-x)=210

solving the above quadration equation two possible values(marks) of x(mathematics) exists.

At x=12, y=18 & at x=13, y=17   

Answers 6 Comments
Dislike Bookmark

Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

5

Board

State, CBSE, ISC/ICSE

ISC/ICSE Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

5

Board

State, CBSE, ISC/ICSE

ISC/ICSE Subjects taught

Mathematics

CBSE Subjects taught

Physics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

5

Board

State, CBSE, ICSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

BCom Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BCom Tuition

3

BCom Subject

Business Mathematics and Statistics

Type of class

Regular Classes, Crash Course

Class strength catered to

Group Classes

Taught in School or College

No

No Reviews yet!

Answers by Vikash P. (10)

Answered on 19/06/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3

According to the problem statement: ________(i) ________(ii) Putting the value of in equation (i) we get ...more

According to the problem statement: ________(i)

________(ii)

Putting the value of  in equation (i) we get 

Answers 13 Comments
Dislike Bookmark

Answered on 19/06/2019 Learn CBSE/Class 9 +1 CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/ Class 10 Situational problems based on quadratic equations.

Use the sum of AP series concept, where Sn= 66, first term a1=1, common difference d=1, then find n. Putting all the values in the formula of Sn we get, n^2+n-132=0 Required answer= n+1 which will come to be 12 (OPTION B)
Answers 3 Comments
Dislike Bookmark

Answered on 19/06/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3

Let Mathematics marks be x and that of English be y, Solve the following equations: x+y=30____(i) (x+2)(y-3)=210___(ii) In equtation (ii) substitute y in terms of x using equation (i), then we get (x+2)(27-x)=210 solving the above quadration equation two possible... ...more

Let Mathematics marks be x and that of English be y,

Solve the following equations: x+y=30____(i)

                                            (x+2)(y-3)=210___(ii)

In equtation (ii) substitute y in terms of x using equation (i), then we get (x+2)(27-x)=210

solving the above quadration equation two possible values(marks) of x(mathematics) exists.

At x=12, y=18 & at x=13, y=17   

Answers 6 Comments
Dislike Bookmark

Contact

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Vikash P. describes himself as An Engineer. He conducts classes in BCom Tuition, Class 10 Tuition and Class 11 Tuition. Vikash is located in Bansdroni, Kolkata. Vikash takes Regular Classes- at his Home and Online Classes- via online medium. He has 5 years of teaching experience . Vikash is pursuing Bachelor of Technology (B.Tech.) from FIEM. He is well versed in English and Hindi.

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