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Vivek Pothu Quantitative Aptitude trainer in Hyderabad/>

Vivek Pothu

P & T Colony, Hyderabad, India - 500039.

Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

I had been teaching Maths for tenth class and also I took classes on quantitative aptitude and reasoning .

Languages Spoken

Hindi

Telugu

English

Education

NIT 2013

Master of Computer Applications (M.C.A.)

Address

P & T Colony, Hyderabad, India - 500039

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Teaches

Quantitative Aptitude Coaching

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Quantitative Aptitude Coaching

2

Teaching Experience in detail in Quantitative Aptitude Coaching

did mca in nit durgapur, i have experienced in quant and reasoning

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

5

Board

State, CBSE

CBSE Subjects taught

Mathematics, English

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, English

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

English, Mathematics

State Syllabus Subjects taught

English, Mathematics

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

English, Mathematics

State Syllabus Subjects taught

English, Mathematics

Reviews

No Reviews yet! Be the first one to Review

FAQs

1. Which classes do you teach?

I teach Class 10 Tuition, Class 9 Tuition, Class I-V Tuition, Class VI-VIII Tuition and Quantitative Aptitude Classes.

2. Do you provide a demo class?

Yes, I provide a free demo class.

3. How many years of experience do you have?

I have been teaching for 2 years.

Answers by Vivek Pothu (5)

Answered on 15/12/2014 Learn Tuition/Class VI-VIII Tuition

ans:: circumference of a circle id 2*pi*r ,here radius r then 2*pi*r=6*r+2 2*.PI.*r-6*r=2, r( 2*(22/7) - 6 )=2, i.e pi=22/7 we get r= 7. then area of circle is = pi*r*r = (22/7)*7*7= 154.....
Answers 74 Comments
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Answered on 13/12/2014 Learn Tuition/Class VI-VIII Tuition

It very simple radios mean half of the diameter .if radios 'r' and diameter 'D',then D=2r, here no need of height ,D=2*2.25=4.5.
Answers 98 Comments
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Answered on 13/12/2014 Learn Exam Coaching/Quantitative Aptitude

First one is practice and then think about problem until your satisfaction with different ways then discuss start discussion with friends who knows quantitative aptitude ....,
Answers 62 Comments
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Answered on 11/12/2014 Learn Exam Coaching/Quantitative Aptitude

40
Answers 74 Comments
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Teaches

Quantitative Aptitude Coaching

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Quantitative Aptitude Coaching

2

Teaching Experience in detail in Quantitative Aptitude Coaching

did mca in nit durgapur, i have experienced in quant and reasoning

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

5

Board

State, CBSE

CBSE Subjects taught

Mathematics, English

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, English

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

English, Mathematics

State Syllabus Subjects taught

English, Mathematics

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

English, Mathematics

State Syllabus Subjects taught

English, Mathematics

No Reviews yet! Be the first one to Review

Answers by Vivek Pothu (5)

Answered on 15/12/2014 Learn Tuition/Class VI-VIII Tuition

ans:: circumference of a circle id 2*pi*r ,here radius r then 2*pi*r=6*r+2 2*.PI.*r-6*r=2, r( 2*(22/7) - 6 )=2, i.e pi=22/7 we get r= 7. then area of circle is = pi*r*r = (22/7)*7*7= 154.....
Answers 74 Comments
Dislike Bookmark

Answered on 13/12/2014 Learn Tuition/Class VI-VIII Tuition

It very simple radios mean half of the diameter .if radios 'r' and diameter 'D',then D=2r, here no need of height ,D=2*2.25=4.5.
Answers 98 Comments
Dislike Bookmark

Answered on 13/12/2014 Learn Exam Coaching/Quantitative Aptitude

First one is practice and then think about problem until your satisfaction with different ways then discuss start discussion with friends who knows quantitative aptitude ....,
Answers 62 Comments
Dislike Bookmark

Answered on 11/12/2014 Learn Exam Coaching/Quantitative Aptitude

40
Answers 74 Comments
Dislike Bookmark

Vivek Pothu conducts classes in Class 10 Tuition, Class 9 Tuition and Class I-V Tuition. Vivek is located in P & T Colony, Hyderabad. Vivek takes at students Home and Regular Classes- at his Home. He has 5 years of teaching experience . Vivek has completed Master of Computer Applications (M.C.A.) from NIT in 2013. He is well versed in Hindi, Telugu and English.

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