Tajuddin Shaik photo

Tajuddin Shaik

Tutor

Jubilee Hills, Hyderabad, India- 500033.

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Details verified of Tajuddin Shaik

Identity

Education

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Overview

I am an experienced, passionate and qualified tutor over 13 years of experience in teaching Maths, Vedic Maths, Quantitative aptitude, Reasoning, Vedic Maths, Excel, Chess and Primavera P6 software.
I have helped hundreds of students to overcome their fear of maths.

I am joyful and fills abundant confidence in my students.

Demo Class

No

Languages Spoken

Hindi, English, Telugu

Education

Bachelor of Engineering (B.E.) from Andhra University in 2007.

Master of Business Administration (M.B.A.) from NICMAR, Pune in 2016.

Address

Jubilee Hills, Hyderabad, India- 500033.

Quantitative Aptitude Coaching Overview

Quantitative Aptitude Coaching

Class Location

Student's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Quantitative Aptitude Coaching

6

Teaching Experience in detail in Quantitative Aptitude Coaching

Whereever I go. I was given best teacher award in quantitative aptitude. I will assure you my best services

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Reviews

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Answers by Tajuddin Shaik (3)

"What is the value of Cos90+Tan90+Cot90?" in   Tuition/Class IX-X Tuition

Infinity or not defined because Tan 90 is not defined

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"A train travelling at 60km per hour leaves station A at 3.00.p .m. and an another train leaves the same station in the same direction at 5.00 p.m. at the speed of 75 km per hr.How many kilometres from station A will the trains be together?" in   Tuition/Class VI-VIII Tuition

Diff of Speeds between trains = 75Km - 60 Km Per Hour = 15 Km (Nothing but relative speed between 2 trains) Train with 60Km per hour speed have traveled 60Kmph x (5Pm - 3Pm) = 120Km at 5Pm which is starting time of 2nd train with 75Kmph So the train with 75Kmph have to cover additional 120Km with a relative speed of 15Kmph. therefore time taken at the meeting point = 120Km / 15Kmph = 8 Hours And distance from the starting point = 8 Hours x 75Kmph = 600Km (Because 2nd train took 8hrs at the meeting point with 75Kmph speed). So answer is 600Km. However there is a shortcut to this Distance of Meeting point = speed of the slower train x (time difference) / relative velocity x Speed of the faster Train = V1 x V2 x (t2-t1) / (V2-V1) = 60 x 75 x (5-3) / (75-60) = 600 Km Relative Velocity = V2 - V1 if the trains are travelling in the same direction = V2+ V1 if the trains are travelling in the opposite direction. Hope i cleared your concept. Thank you

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"How much can I expect to pay as fees for 1-1 chess home tutor for my son?" in   Sports Coaching/Chess Coaching, Tuition Fee

Rs.300-500 an hour. If you could give me a chance, I will make your son 1500 rated player in an year

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Tajuddin Shaik address

x
Quantitative Aptitude Coaching

Class Location

Student's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Quantitative Aptitude Coaching

6

Teaching Experience in detail in Quantitative Aptitude Coaching

Whereever I go. I was given best teacher award in quantitative aptitude. I will assure you my best services

Chess Coaching classes

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Chess Coaching classes

15

Teaching Experience in detail in Chess Coaching classes

See the demo and Judge!! I'm a 1800 rated player

MS Project Training

Class Location

Online (video chat via skype, google hangout etc)

Years of Experience in MS Project Training

7

Teaching Experience in detail in MS Project Training

I'm working for a consultancy which provide services for Planning solutions using MSP and Primavera.

BTech Tuition

BTech Branch

BTech Civil Engineering

Experience in School or College

Type of class

Crash Course

Class strength catered to

One on one/ Private Tutions

Taught in School or College

Yes

BTech Civil subjects

Resource Management, Surveying, Estimation And Costing

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in BTech Tuition

5

Teaching Experience in detail in BTech Tuition

I'm a manager in a reputed firm.

Class 9 Tuition

Board

ICSE, State, CBSE

CBSE Subjects taught

Computer Practices, Mathematics, Telugu

ICSE Subjects taught

Mathematics, Computer Application

Experience in School or College

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Telugu

Class Location

Online (video chat via skype, google hangout etc)

Years of Experience in Class 9 Tuition

10

Teaching Experience in detail in Class 9 Tuition

See the demo and decide

Class 10 Tuition

Board

ICSE, State, CBSE

CBSE Subjects taught

Computer Practices, Mathematics, Telugu

ICSE Subjects taught

Mathematics, Computer Application

Experience in School or College

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Telugu

Class Location

Online (video chat via skype, google hangout etc)

Years of Experience in Class 10 Tuition

10

Teaching Experience in detail in Class 10 Tuition

See the demo and decide

Bank Clerical Exam Coaching classes

Target section catered to

Interview prep, Quantitative aptitude/ Numerical ability

Class Location

Online (video chat via skype, google hangout etc)

Years of Experience in Bank Clerical Exam Coaching classes

8

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No Reviews yet! Be the first one to Review

"What is the value of Cos90+Tan90+Cot90?" in   Tuition/Class IX-X Tuition

Infinity or not defined because Tan 90 is not defined

0
|
0

"A train travelling at 60km per hour leaves station A at 3.00.p .m. and an another train leaves the same station in the same direction at 5.00 p.m. at the speed of 75 km per hr.How many kilometres from station A will the trains be together?" in   Tuition/Class VI-VIII Tuition

Diff of Speeds between trains = 75Km - 60 Km Per Hour = 15 Km (Nothing but relative speed between 2 trains) Train with 60Km per hour speed have traveled 60Kmph x (5Pm - 3Pm) = 120Km at 5Pm which is starting time of 2nd train with 75Kmph So the train with 75Kmph have to cover additional 120Km with a relative speed of 15Kmph. therefore time taken at the meeting point = 120Km / 15Kmph = 8 Hours And distance from the starting point = 8 Hours x 75Kmph = 600Km (Because 2nd train took 8hrs at the meeting point with 75Kmph speed). So answer is 600Km. However there is a shortcut to this Distance of Meeting point = speed of the slower train x (time difference) / relative velocity x Speed of the faster Train = V1 x V2 x (t2-t1) / (V2-V1) = 60 x 75 x (5-3) / (75-60) = 600 Km Relative Velocity = V2 - V1 if the trains are travelling in the same direction = V2+ V1 if the trains are travelling in the opposite direction. Hope i cleared your concept. Thank you

0
|
0

"How much can I expect to pay as fees for 1-1 chess home tutor for my son?" in   Sports Coaching/Chess Coaching, Tuition Fee

Rs.300-500 an hour. If you could give me a chance, I will make your son 1500 rated player in an year

0
|
0

Tajuddin Shaik describes himself as Tutor. He conducts classes in BTech Tuition, Bank Clerical Exam Coaching and Chess Coaching. Tajuddin is located in Jubilee Hills, Hyderabad. Tajuddin takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. He has 15 years of teaching experience . Tajuddin has completed Bachelor of Engineering (B.E.) from Andhra University in 2007 and Master of Business Administration (M.B.A.) from NICMAR, Pune in 2016. HeĀ is well versed in Hindi, English and Telugu.

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