Krishan Shetty

Madhapur, Hyderabad, India - 500018

Krishan Shetty photo

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Krishan Shetty

Chemistry Tutor

Madhapur, Hyderabad, India - 500018.

5.0

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Education

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Overview

I am a tutor taking classes in chemistry. I have been doing so for the past two years and also a chemical engineer by designation and profession (and have 5 years of experience in that as well). I usually take classes for 9th to 11th standard chemistry.

Languages Spoken

Hindi Proficient

English Proficient

Marathi Proficient

Education

Institute of Chemical Technology, Mumbai 2014

Bachelor of Engineering (B.E.)

Address

Madhapur, Hyderabad, India - 500018

Verified Info

ID Verified

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Email Verified

Demo Class

Yes, charged

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Class 10 Tuition Overview

Class 10 Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 10 Tuition

2

Board

IGCSE, ICSE, CBSE, State, International Baccalaureate

IB Subjects taught

Chemistry

CBSE Subjects taught

Science

ICSE Subjects taught

Chemistry

IGCSE Subjects taught

Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Science

Teaching Experience in detail in Class 10 Tuition

Hi guys, I have 2 years of experience in teaching kids from 9th to 12th standard for CBSE to IB level .

Reviews

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FAQs

1. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition, Class 8 Tuition and Class 9 Tuition Classes.

2. Do you provide a demo class?

Yes, I provide a free demo class.

3. How many years of experience do you have?

I have been teaching for 2 years.

Answers by Krishan Shetty (1)

Answered on 21 Aug CBSE/Class 11/Science/Chemistry

There are two ways to solve it: 1) Knowing the mass of one atomic mass unit: Mass of one atomic mass unit = 1.66 * 10^-24 gms Therefore mass of 1000 atoms of nitrogen = Atomic mass of nitrogen * 1000 atoms * Mass of one atomic mass unit = 14 amu/atom * 1000 atoms *1.66 * 10^-24 g/amu = 2.32 * 10^-20... ...more

There are two ways to solve it:

1) Knowing the mass of one atomic mass unit:

Mass of one atomic mass unit = 1.66 * 10^-24 gms

Therefore mass of 1000 atoms of nitrogen = Atomic mass of nitrogen * 1000 atoms * Mass of one atomic mass unit

= 14 amu/atom * 1000 atoms *1.66 * 10^-24 g/amu

= 2.32 * 10^-20 g

2) Knowin mass of one mole of atoms

One mole of nitrogen atoms = 6.022 * 10^23 atoms of nitrogen = 14 g of nitrogen

Therefore 1000 atoms of nitrogen = 14 g/(6.023 *10^23) *1000 atoms = 2.32 * 10^-20 gm

Answers 16 Comments
Dislike Bookmark

Krishan ShettyDirections

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Class 10 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 10 Tuition

2

Board

IGCSE, ICSE, CBSE, State, International Baccalaureate

IB Subjects taught

Chemistry

CBSE Subjects taught

Science

ICSE Subjects taught

Chemistry

IGCSE Subjects taught

Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Science

Teaching Experience in detail in Class 10 Tuition

Hi guys, I have 2 years of experience in teaching kids from 9th to 12th standard for CBSE to IB level .

Class 11 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 11 Tuition

2

Board

ISC/ICSE, CBSE, IGCSE, International Baccalaureate, State

IB Subjects taught

Chemistry

CBSE Subjects taught

Chemistry

IGCSE Subjects taught

Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Chemistry

Class 9 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 9 Tuition

2

Board

IGCSE, ICSE, CBSE, International Baccalaureate

IB Subjects taught

Chemistry

CBSE Subjects taught

Science

ICSE Subjects taught

Chemistry

IGCSE Subjects taught

Chemistry

Taught in School or College

No

Teaching Experience in detail in Class 9 Tuition

Hi guys, I have 2 years of experience in teaching kids from 9th grade to 12th grade for chemistry subject from CBSE to IB grade.

Class 8 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 8 Tuition

2

Board

ICSE, IGCSE, International Baccalaureate, CBSE

IB Subjects taught

Science

CBSE Subjects taught

Science

ICSE Subjects taught

Chemistry

IGCSE Subjects taught

Science

Taught in School or College

No

Teaching Experience in detail in Class 8 Tuition

Hi guys, I have 2 years of experience in teaching kids from 9th to 12th grade for chemistry and science for CBSE to IB level.

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No Reviews yet! Be the first one to Review

Answers by Krishan Shetty (1)

Answered on 21 Aug CBSE/Class 11/Science/Chemistry

There are two ways to solve it: 1) Knowing the mass of one atomic mass unit: Mass of one atomic mass unit = 1.66 * 10^-24 gms Therefore mass of 1000 atoms of nitrogen = Atomic mass of nitrogen * 1000 atoms * Mass of one atomic mass unit = 14 amu/atom * 1000 atoms *1.66 * 10^-24 g/amu = 2.32 * 10^-20... ...more

There are two ways to solve it:

1) Knowing the mass of one atomic mass unit:

Mass of one atomic mass unit = 1.66 * 10^-24 gms

Therefore mass of 1000 atoms of nitrogen = Atomic mass of nitrogen * 1000 atoms * Mass of one atomic mass unit

= 14 amu/atom * 1000 atoms *1.66 * 10^-24 g/amu

= 2.32 * 10^-20 g

2) Knowin mass of one mole of atoms

One mole of nitrogen atoms = 6.022 * 10^23 atoms of nitrogen = 14 g of nitrogen

Therefore 1000 atoms of nitrogen = 14 g/(6.023 *10^23) *1000 atoms = 2.32 * 10^-20 gm

Answers 16 Comments
Dislike Bookmark

Krishan Shetty describes himself as Chemistry Tutor. He conducts classes in Class 10 Tuition, Class 11 Tuition and Class 8 Tuition. Krishan is located in Madhapur, Hyderabad. Krishan takes at students Home and Online Classes- via online medium. He has 2 years of teaching experience . Krishan has completed Bachelor of Engineering (B.E.) from Institute of Chemical Technology, Mumbai in 2014. HeĀ is well versed in Hindi, English and Marathi.

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