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Bommana Praneeth Kumar Reddy Class 9 Tuition trainer in Hyderabad

Bommana Praneeth Kumar Reddy

Saidabad, Hyderabad, India - 500059.

Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

Bommana Praneeth Kumar Reddy conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Bommana is located in Saidabad, Hyderabad. Bommana takes at students Home and Regular Classes- at his Home. HeĀ is well versed in Telugu, English and Hindi.

Languages Spoken

Telugu

English

Hindi

Address

Saidabad, Hyderabad, India - 500059

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Teaches

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Quantitative Aptitude Coaching

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Verbal Aptitude Coaching

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Non-Verbal Aptitude Coaching

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Vedic Maths Training classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Logic, Mathematics

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Logic, Mathematics

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

English, Mathematics

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

English, Mathematics

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

English, Mathematics

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics, English, Social Science

Reviews

No Reviews yet! Be the first one to Review

FAQs

1. Which school boards of Class 10 do you teach for?

State

2. Do you have any prior teaching experience?

No

3. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition, Class I-V Tuition, Non-Verbal Aptitude and Quantitative Aptitude Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for less than a year.

Answers by Bommana Praneeth Kumar Reddy (3)

Answered on 11/09/2017 Learn Exam Coaching/Quantitative Aptitude

By doing the problem in R.S.Agarwal's quantitative aptitude book youcan easily get 30+ in CPT
Answers 4 Comments
Dislike Bookmark

Answered on 29/08/2017 Learn Exam Coaching/Quantitative Aptitude

It's 166644591.33... (or) For a number to be divisible by 6, it has to be divisible by 2 & 3 both. Last digit is 8 and so divisible by 2. Divisibility by 3, add all digits up to the point you get single digit. In this case, first you get 65, add further to get 11 and then 2. As it is not 0, 3, 6 or... ...more
It's 166644591.33... (or) For a number to be divisible by 6, it has to be divisible by 2 & 3 both. Last digit is 8 and so divisible by 2. Divisibility by 3, add all digits up to the point you get single digit. In this case, first you get 65, add further to get 11 and then 2. As it is not 0, 3, 6 or 9, the given number it's not divisible by 3 and hence not divisible by 6.
Answers 2 Comments
Dislike Bookmark

Teaches

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Quantitative Aptitude Coaching

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Verbal Aptitude Coaching

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Non-Verbal Aptitude Coaching

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Vedic Maths Training classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Logic, Mathematics

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Logic, Mathematics

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

English, Mathematics

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

English, Mathematics

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

English, Mathematics

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics, English, Social Science

No Reviews yet! Be the first one to Review

Answers by Bommana Praneeth Kumar Reddy (3)

Answered on 11/09/2017 Learn Exam Coaching/Quantitative Aptitude

By doing the problem in R.S.Agarwal's quantitative aptitude book youcan easily get 30+ in CPT
Answers 4 Comments
Dislike Bookmark

Answered on 29/08/2017 Learn Exam Coaching/Quantitative Aptitude

It's 166644591.33... (or) For a number to be divisible by 6, it has to be divisible by 2 & 3 both. Last digit is 8 and so divisible by 2. Divisibility by 3, add all digits up to the point you get single digit. In this case, first you get 65, add further to get 11 and then 2. As it is not 0, 3, 6 or... ...more
It's 166644591.33... (or) For a number to be divisible by 6, it has to be divisible by 2 & 3 both. Last digit is 8 and so divisible by 2. Divisibility by 3, add all digits up to the point you get single digit. In this case, first you get 65, add further to get 11 and then 2. As it is not 0, 3, 6 or 9, the given number it's not divisible by 3 and hence not divisible by 6.
Answers 2 Comments
Dislike Bookmark

Bommana Praneeth Kumar Reddy conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Bommana is located in Saidabad, Hyderabad. Bommana takes at students Home and Regular Classes- at his Home. HeĀ is well versed in Telugu, English and Hindi.

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