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Abhinav Kalra Microsoft Excel trainer in Gurgaon

Abhinav Kalra

Tutor

Sector 15, Gurgaon, India - 122022.

1 Student

Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

I can teach each and every topics very easily and make it stronger for the students.

Languages Spoken

Hindi

English

Education

NIT Kuruskshetra

Bachelor of Technology (B.Tech.)

Address

Sector 15, Gurgaon, India - 122022

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Teaches

Microsoft Excel Training classes
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Microsoft Excel Training classes

5

Teaches following Excel features

Advanced Excel, Basic Excel

Class 11 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Mathematics, Physics

CBSE Subjects taught

Mathematics, Physics

Taught in School or College

Yes

State Syllabus Subjects taught

Physics, Mathematics

Class 12 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

2

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Mathematics, Physics

CBSE Subjects taught

Mathematics, Physics

Taught in School or College

Yes

State Syllabus Subjects taught

Physics, Mathematics

Reviews

No Reviews yet! Be the first one to Review

FAQs

1. What Excel features do you teach?

Advanced Excel and Basic Excel

2. Which classes do you teach?

I teach Class 11 Tuition, Class 12 Tuition and Microsoft Excel Training Classes.

3. Do you provide a demo class?

Yes, I provide a free demo class.

4. How many years of experience do you have?

I have been teaching for 5 years.

Answers by Abhinav Kalra (2)

Answered on 04/01/2018 Learn CBSE/Class 11/Science/Physics +1 Tuition/Class XI-XII Tuition (PUC)

perpendicular force acting on an object will only change the direction of its velocity, not its magnitude since there is no force in the direction of its velocity.
Answers 8 Comments
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Answered on 04/01/2018 Learn CBSE/Class 11/Science/Physics +1 Tuition/Class XI-XII Tuition (PUC)

16N and 12N are acting in mutually perpendicular direction. So resultant force = â??(16² + 12²) = â??256+144 = â??400 = 20N mass of body = 200 kg acceleration = net force/mass = 20/200 = 0.1 m/s2
Answers 20 Comments
Dislike Bookmark

Teaches

Microsoft Excel Training classes
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Microsoft Excel Training classes

5

Teaches following Excel features

Advanced Excel, Basic Excel

Class 11 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Mathematics, Physics

CBSE Subjects taught

Mathematics, Physics

Taught in School or College

Yes

State Syllabus Subjects taught

Physics, Mathematics

Class 12 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

2

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Mathematics, Physics

CBSE Subjects taught

Mathematics, Physics

Taught in School or College

Yes

State Syllabus Subjects taught

Physics, Mathematics

No Reviews yet! Be the first one to Review

Answers by Abhinav Kalra (2)

Answered on 04/01/2018 Learn CBSE/Class 11/Science/Physics +1 Tuition/Class XI-XII Tuition (PUC)

perpendicular force acting on an object will only change the direction of its velocity, not its magnitude since there is no force in the direction of its velocity.
Answers 8 Comments
Dislike Bookmark

Answered on 04/01/2018 Learn CBSE/Class 11/Science/Physics +1 Tuition/Class XI-XII Tuition (PUC)

16N and 12N are acting in mutually perpendicular direction. So resultant force = â??(16² + 12²) = â??256+144 = â??400 = 20N mass of body = 200 kg acceleration = net force/mass = 20/200 = 0.1 m/s2
Answers 20 Comments
Dislike Bookmark

Abhinav Kalra describes himself as Tutor. He conducts classes in Class 11 Tuition, Class 12 Tuition and Microsoft Excel Training. Abhinav is located in Sector 15, Gurgaon. Abhinav takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. He has 5 years of teaching experience . Abhinav has completed Bachelor of Technology (B.Tech.) from NIT Kuruskshetra. He is well versed in Hindi and English.

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