## Class I-V Tuition

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Naga Vija Lakshmi 30/05/2015 in  Class I-V Tuition

Prayashi replied | 07/07/2016

Anchita replied | 25/10/2016

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Madhu 31/05/2015 in  Class I-V Tuition

Amrutha replied | 12/12/2015

2x+3y=6 (a)
4x+3y=9 (b)
Multiply (a) with 4
And multiply (b) with 2, so we get
+ 8x+12y=24 (a)
+ 8x+6y=18 (b)
(-) (-) (-) [b's signs will become inverse] so get,
+6y=6 ( because +8x -8x=0, +12y-6y=+6y, 24-18=6)
Now, move the +6 to right side, then it decides to RHS 6. So we get,
Y=6/6
Y=1.-----we find y value.
Now...  more»
2x+3y=6 (a)
4x+3y=9 (b)
Multiply (a) with 4
And multiply (b) with 2, so we get
+ 8x+12y=24 (a)
+ 8x+6y=18 (b)
(-) (-) (-) [b's signs will become inverse] so get,
+6y=6 ( because +8x -8x=0, +12y-6y=+6y, 24-18=6)
Now, move the +6 to right side, then it decides to RHS 6. So we get,
Y=6/6
Y=1.-----we find y value.
Now substitute y value into a.
2x+3(1)=6
2x+3=6
2x=6-3
2x=3
x=3/2
x=1.5

So x= 1.5 and y= 1

You can substitute x and y values in a and you'll get the came value of the value.
Thank you. «less

M

Mumal replied | 13/12/2015

X=3/2 and placing the value of x in equation 1 ie.2x+3y=6. V get value of y as 1

X= 1.5
Y=1

C

Chetana replied | 15/12/2015

2x+3y=6
4x+3y=9
________
-2x =-3
x=3/2

consider any one of the equation and substitute the x value
from equation 1

2x+3y=6
2(3/2)+3y=6
3+3y=6
3y=6-3
3y=3
y=1

C

Chetana replied | 15/12/2015

2x+3y =6
4x+3y =9
_________
-2x =-3
x =3/2
substitute the x value in any one of the equation
2x+3y =6
2(3/2)+3y=6
3+3y =6
3y =6-3
y =3/3
y =1

M

Mallika replied | 13/02/2016

Subtract:-
2x+3y=6
4x+3y=9
-2x = -3
X = 3/2

Substitute x value in equation
2*3\2 + 3y =6
3+3y=6
3y=6-3
Y=3/3
Y=1

V.narasimha replied | 16/02/2016

2x + 3y=6
4x +3y =9
- - -
-----------------
-2x 0=-3
-2x=-3
X=3/2.
Substitute in " x "volume below the equation.
4x + 3y=9
4(3/2) +3y=9. (X =3/2)
2(3)+3y=9
6+3y=9
3y=9-6
3y=3
y=3/3.
y=1
Now the both x & y volumes are substitute any above the equation
2x+3y=6
2(3/2)+3(1)=6
3+3=6
6=6

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Kavita 16/05/2015 in  Class I-V Tuition

Neha replied | 30/06/2015

Johannes Kepler

Anchita replied | 25/10/2016

Johannes Kepler

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Puneet Kr. 10/04/2015 in  Class I-V Tuition

Roslin replied | 25/04/2015

B: ribosomes

S

Samudrala replied | 22 Mar

Lysosomes.

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Puneet Kr. 10/04/2015 in  Class I-V Tuition

Priya replied | 15/06/2015

Cytoplasm

Anchita replied | 25/10/2016

Cytoplasm.

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Baljeet Singh 05/04/2015 in  Class I-V Tuition

J

Jyothi Gaurilakshmi replied | 19/04/2015

5

Anchita replied | 25/10/2016

0

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Baljeet Singh 03/04/2015 in  Class I-V Tuition

D

Dayakar replied | 08/07/2016

it has to be 10, as zero is not a multiple of ten nor a significant number...

Anchita replied | 25/10/2016

0 because it is less then 5.

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Kotwal 31/03/2015 in  Class I-V Tuition

Prayashi replied | 07/07/2016

22/7 or 3.14

Anchita replied | 25/10/2016

its 22/7= 3.14

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Aman 31/03/2015 in  Class I-V Tuition

Z

Zeba replied | 10/01/2016

it is an integer

Anchita replied | 25/10/2016

False.Natural numbers starts from 1.

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Aman 31/03/2015 in  Class I-V Tuition

Arpita replied | 01/12/2015

Trigonometry.

Anchita replied | 25/10/2016

Trigonometry.

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Aman 31/03/2015 in  Class I-V Tuition

J

Jyothi replied | 17/04/2015

MEDIAN

Vandana replied | 18/04/2015

Median

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Aman 31/03/2015 in  Class I-V Tuition

Arpita replied | 01/12/2015

googol

A

googol

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Aman 31/03/2015 in  Class I-V Tuition

R

Ranjeeth Reddy replied | 11/05/2015

Arpita replied | 01/12/2015

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Kavita 26/03/2015 in  Class I-V Tuition

Rahul replied | 15/04/2015

Multiply both the numerator and denominator of first fraction with the denominator of second fraction. Let the answer to this step be A.
Now multiply the numerator and denominator of the second fraction with the denominator of the first number. Let that answer is this step be B.

Mamata replied | 07/12/2015

using LCM of denominator and convert it to like fraction and then add
or
criss cross multiplication , multiply numerator of 1st fraction and denominator of 2nd fraction then add this result with multiplication of denominator of 1st fraction and numerator of 2nd fraction .
then divide this result by multiplication of both denominator
2/3+5/4
= (2*4+3*5)/3*4...  more»
using LCM of denominator and convert it to like fraction and then add
or
criss cross multiplication , multiply numerator of 1st fraction and denominator of 2nd fraction then add this result with multiplication of denominator of 1st fraction and numerator of 2nd fraction .
then divide this result by multiplication of both denominator
2/3+5/4
= (2*4+3*5)/3*4
= 23/12 «less

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T

Arpita replied | 01/12/2015

Yes. B.Ed is compulsory now.

Anchita replied | 31/10/2016

Yes, B.Ed is mandatory if you want to apply for schools.

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S

Sindu 24/03/2015 in  Class I-V Tuition

Anitha replied | 09/04/2015

yes it is

Anchita replied | 26/10/2016

Communication is like a necessity these days, if you want to showcase your capabilities, understand each other or want to praise, you need to communicate.

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Sutapa 19/03/2015 in  Class I-V Tuition

Mukti replied | 09/04/2015

Dear Friend, since you have passed MA and if you have good command over your English and your are a confident woman go ahead with all standard students. Why only Montessori?

Anchita replied | 26/10/2016

You can start taking tuition at home whenever you want, there is a lot of scope, but as for teaching in schools, B.Ed is required these days as per the knowledge i have.

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M

Mukund 15/03/2015 in  Class I-V Tuition

S

Sakina replied | 20/03/2015

Titan

Anchita replied | 26/10/2016

Titan is Saturn's largest moon and the second largest in the solar system (after Ganymede of Jupiter). It is the only moon in the solar system with clouds and a dense, planet-like atmosphere.

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M

Mukund 15/03/2015 in  Class I-V Tuition

D

Deepanshi replied | 22/03/2015

There are some rocks present on moon's surface from which one can extract water. So this is a sign of life on Mars....

Akanksha replied | 11/06/2016

Google it , it would b better

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M

Mukund 15/03/2015 in  Class I-V Tuition

Ankit replied | 18/03/2015

About 100 millions or billions or more.

Anchita replied | 26/10/2016

at least 100 billion planets.

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Kavita 11/03/2015 in  Class I-V Tuition

Arpita replied | 01/12/2015

8 planets-- mercury, Venus, Mars, Earth, Jupiter, Saturn, Uranus, Neptune.

Anchita replied | 27/10/2016

There are 8 planets- Mercury, Venus, Mars, Earth, Jupiter Saturn, Uranus, Neptune

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S

Sugantha 09/03/2015 in  Class I-V Tuition

N

Nitin replied | 16/03/2015

Igneous Rock

Anchita replied | 27/10/2016

Igneous Rock

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S

Sugantha 09/03/2015 in  Class I-V Tuition

Amit replied | 13/03/2015

A) condense

Anchita replied | 27/10/2016

Condense into a liquid.

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S

Sugantha 09/03/2015 in  Class I-V Tuition

Amit replied | 13/03/2015

Humidity is the correct option

Anchita replied | 31/10/2016

Humidity.

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S

Swagata replied | 19/03/2015

Anchita replied | 27/10/2016

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