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Shubham Rautela Class 10 trainer in Chandigarh

Shubham Rautela

Bachelor's in computer applications, can teach computer science, maths, science social sciences.

Adarsh Nagar, Chandigarh, India - 160103.

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Overview

I am student pursuing a degree in Library sciences. I have completed my bachelor's in computer applications in 2020. Maths, chemistry and computer sciences are my strong subjects. I can teach all other subjects to students in classes 1-10.

Languages Spoken

Hindi Mother Tongue (Native)

English Basic

Education

Punjab University 2020

Bachelor of Computer Applications (B.C.A.)

Address

Adarsh Nagar, Chandigarh, India - 160103

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Teaches

Class 10 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

1

Board

CBSE, ICSE, State

State boards taught

Delhi State Board, Uttar Pradesh State Board, Uttarakhand State Board, Punjab State Board

CBSE Subjects taught

Hindi, Computer Practices, Information and Comunication Technology, Science, Social science, Mathematics

ICSE Subjects taught

Computer Application, Chemistry, Physics, History and Civics, Geography, Mathematics, Hindi, Biology

Experience in School or College

I have taught students from class 1-10 previously.

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Science, Hindi, EVS, Social Science

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 10 do you teach for?

CBSE, ICSE and State

2. Do you have any prior teaching experience?

Yes

3. Which classes do you teach?

I teach Class 10 Tuition Class.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 1 year.

Answers by Shubham Rautela (1)

Answered on 20/04/2022 Learn CBSE/Class 2/Maths/Mental Arithmetic +1 Tuition

Let P be the age of first person and Q be the age of second person. It is given that their ratio is 5:7, so we can write P/Q=5/7 After six years P's age will be P + 6, it is given that the difference between Q's present age and P's age after 6 years is 2. So we can write Q - (P+6) = 2 Putting value of... ...more

Let P be the age of first person and Q be the age of second person.

It is given that their ratio is 5:7, so we can write

P/Q=5/7

After six years P's age will be P + 6, it is given that the difference between Q's present age and P's age after 6 years is 2. So we can write

Q - (P+6) = 2

Putting value of P from previous equation

Q - (5Q/7 + 2) = 2

7Q - 5Q - 14 = 14

2Q = 28

Q = 14

Therefore P will 5Q/7 = 5*14/7 = 10.

 

 

 

 

 

 

 

 

 

Answers 353 Comments
Dislike Bookmark

Teaches

Class 10 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

1

Board

CBSE, ICSE, State

State boards taught

Delhi State Board, Uttar Pradesh State Board, Uttarakhand State Board, Punjab State Board

CBSE Subjects taught

Hindi, Computer Practices, Information and Comunication Technology, Science, Social science, Mathematics

ICSE Subjects taught

Computer Application, Chemistry, Physics, History and Civics, Geography, Mathematics, Hindi, Biology

Experience in School or College

I have taught students from class 1-10 previously.

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Science, Hindi, EVS, Social Science

No Reviews yet!

Answers by Shubham Rautela (1)

Answered on 20/04/2022 Learn CBSE/Class 2/Maths/Mental Arithmetic +1 Tuition

Let P be the age of first person and Q be the age of second person. It is given that their ratio is 5:7, so we can write P/Q=5/7 After six years P's age will be P + 6, it is given that the difference between Q's present age and P's age after 6 years is 2. So we can write Q - (P+6) = 2 Putting value of... ...more

Let P be the age of first person and Q be the age of second person.

It is given that their ratio is 5:7, so we can write

P/Q=5/7

After six years P's age will be P + 6, it is given that the difference between Q's present age and P's age after 6 years is 2. So we can write

Q - (P+6) = 2

Putting value of P from previous equation

Q - (5Q/7 + 2) = 2

7Q - 5Q - 14 = 14

2Q = 28

Q = 14

Therefore P will 5Q/7 = 5*14/7 = 10.

 

 

 

 

 

 

 

 

 

Answers 353 Comments
Dislike Bookmark

Shubham Rautela describes himself as Bachelor's in computer applications, can teach computer science, maths, science social sciences.. He conducts classes in Class 10 Tuition. Shubham is located in Adarsh Nagar, Chandigarh. Shubham takes at students Home and Regular Classes- at his Home. He has 1 years of teaching experience . Shubham has completed Bachelor of Computer Applications (B.C.A.) from Punjab University in 2020. HeĀ is well versed in Hindi and English.

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