Details verified of Atul Kashyap✕
Identity
Education
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Identity is verified based on matching the details uploaded by the Tutor with government databases.
No
Maithili, Hindi, English
Bachelor of Engineering (B.E.) from ASANSOL ENGINEERING COLLEGE -Pursuing.
Asansol, Asansol, India- 713301.
Field tutored for
Micro-Biology, Mathematics, Computer Science, History, Economics
BA Computer Science Subjects
Computer Networks, Theory of Computation, Programming in JAVA, Data Structures, Artificial Intelligence, Computer System Architecture, Database Management Systems, Design and Analysis of Algorithms, Programming Fundamentals using C++, Discrete Structures, Operating Systems
BA Mathematics Subjects
Number Theory, Group Theory, Discrete Mathematics, C++ Programming
Experience in School or College
Type of class
Regular Classes, Crash Course
Class strength catered to
Group Classes, One on one/ Private Tutions
Taught in School or College
No
BA Economics Subjects
Economic History of India, Public Economics, Environmental Economics, Introductory Econometrics, Financial Economics, Indian Economy, Economics of Health and Education, Political Economy
BA Micro- Biology Subjects
Cell Biology
Class Location
Student's Home
Tutor's Home
Online (video chat via skype, google hangout etc)
Years of Experience in BA Tuition
1
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"Write the chemical equation for the reaction involved in Cannizzaro reaction." in CBSE/Class 12/Science/Chemistry, Tuition/Class XI-XII Tuition (PUC)
2 C6H5CHO + KOH = C6H5CH2OH + C6H5COOK The oxidation product is a salt of a carboxylic acid and the reduction product is an alcohol.
"How can you distinguish between propanal and propanone?" in CBSE/Class 12/Science/Chemistry, Tuition/Class XI-XII Tuition (PUC)
(i) Propanal and propanone can be distinguished by the following tests. (a) Tollen's test: Propanal is an aldehyde. Thus, it reduces Tollen's reagent. But, propanone being a ketone does not reduce Tollen's reagent. (b) Fehling's test: Aldehydes respond to Fehling's test, but ketones do not. Propanal being an aldehyde reduces Fehling's solution to a red-brown precipitate of Cu2O, but propanone being a ketone does not. (c) Iodoform test: Aldehydes and ketones having at least one methyl group linked to the carbonyl carbon atom respond to iodoform test. They are oxidized by sodium hypoiodite (NaOI) to give iodoforms. Propanone being a methyl ketone responds to this test, but propanal does not. (ii) Acetophenone and Benzophenone can be distinguished using the iodoform test. Iodoform test: Methyl ketones are oxidized by sodium hypoiodite to give yellow ppt. of iodoform. Acetophenone being a methyl ketone responds to this test, but benzophenone does not. (iii) Phenol and benzoic acid can be distinguished by ferric chloride test. a. Ferric chloride test: Phenol reacts with neutral FeCl3 to form an iron-phenol complex giving violet colouration. But benzoic acid reacts with neutral FeCl3 to give a buff coloured ppt. of ferric benzoate. (iv) Benzoic acid and Ethyl benzoate can be distinguished by sodium bicarbonate test. Sodium bicarbonate test: Acids react with NaHCO3 to produce brisk effervescence due to the evolution of CO2 gas. Benzoic acid being an acid responds to this test, but ethylbenzoate does not. (v) Pentan-2-one and pentan-3-one can be distinguished by iodoform test. Iodoform test: Pentan-2-one is a methyl ketone. Thus, it responds to this test. But pentan-3-one not being a methyl ketone does not respond to this test. (vi) Benzaldehyde and acetophenone can be distinguished by the following tests. (a) Tollen's Test: Aldehydes respond to Tollen's test. Benzaldehyde being an aldehyde reduces Tollen's reagent to give a red-brown precipitate of Cu2O, but acetophenone being a ketone does not. (b) Iodoform test: Acetophenone being a methyl ketone undergoes oxidation by sodium hypoiodite (NaOI) to give a yellow ppt. of iodoform. But benzaldehyde does not respond to this test. (vii) Ethanal and propanal can be distinguished by iodoform test. Iodoform test: Aldehydes and ketones having at least one methyl group linked to the carbonyl carbon atom responds to the iodoform test. Ethanal having one methyl group linked to the carbonyl carbon atom responds to this test. But propanal does not have a methyl group linked to the carbonyl carbon atom and thus, it does not respond to this state.
Atul Kashyap address
xField tutored for
Micro-Biology, Mathematics, Computer Science, History, Economics
BA Computer Science Subjects
Computer Networks, Theory of Computation, Programming in JAVA, Data Structures, Artificial Intelligence, Computer System Architecture, Database Management Systems, Design and Analysis of Algorithms, Programming Fundamentals using C++, Discrete Structures, Operating Systems
BA Mathematics Subjects
Number Theory, Group Theory, Discrete Mathematics, C++ Programming
Experience in School or College
Type of class
Regular Classes, Crash Course
Class strength catered to
Group Classes, One on one/ Private Tutions
Taught in School or College
No
BA Economics Subjects
Economic History of India, Public Economics, Environmental Economics, Introductory Econometrics, Financial Economics, Indian Economy, Economics of Health and Education, Political Economy
BA Micro- Biology Subjects
Cell Biology
Class Location
Student's Home
Tutor's Home
Online (video chat via skype, google hangout etc)
Years of Experience in BA Tuition
1
BTech Computer Science subjects
Microprocessors, Design and Analysis of Algorithms, Artificial Intelligence, Computer Networks, Computer Architecture, Big Data Analytics, Java Programming, Compiler Design, Data Structures and Algorithms, Database Management Systems, Combinatorics, Computer Organization & Design
BTech Branch
BTech Information Science Engineering, BTech 1st Year Engineering, BTech Computer Science Engineering
BTech Information Science subjects
Object Oriented Programming, Database Systems, Operating Systems, Computer Organization & Microprocessor Systems, Artificial Intelligence, Big Data Analytics, Computer Networks, Internet of Things, Data Structures and Algorithms, Design & Analysis of Algorithms
Experience in School or College
Type of class
Regular Classes, Crash Course
Class strength catered to
Group Classes, One on one/ Private Tutions
BTech Mechantronics subjects
Algorithms
Taught in School or College
No
BTech 1st Year subjects
Advanced Mathematics (M2), Basic Electronics, Engineering Chemistry, Engineering Mathematics (M1), Environmental Studies, Engineering Physics, Communication Skills, Computer science, Biology For Engineers
Class Location
Student's Home
Tutor's Home
Online (video chat via skype, google hangout etc)
Years of Experience in BTech Tuition
1
Experience in School or College
BCA Subject
Operation Research, Microprocessor, Operating System Concepts and Networking Management , Problem Solving and Programming , Mathematics, Object Oriented Technologies, Java Programming, Digital Electronics, Algorithm Design , Computer Networks , C Language Programming, Database Management Systems , Computer Architecture, Data structures, Programming in C++
Type of class
Regular Classes, Crash Course
Class strength catered to
Group Classes, One on one/ Private Tutions
Taught in School or College
No
Class Location
Student's Home
Tutor's Home
Online (video chat via skype, google hangout etc)
Years of Experience in BCA Tuition
1
Class Location
Student's Home
Tutor's Home
Online (video chat via skype, google hangout etc)
Years of Experience in C Language Classes
1
Engineering Entrance Exams
IIT JEE Coaching Classes, GATE Coaching Classes
IITJEE Coaching
IIT JEE Foundation Course, IIT JEE Mains Coaching, IIT JEE Integrated Coaching, IIT JEE Crash Course
Type of class
Regular Classes, Crash Course
IIT-JEE Subjects
Chemistry
Class Location
Student's Home
Tutor's Home
Online (video chat via skype, google hangout etc)
Years of Experience in Engineering Entrance Coaching classes
1
Board
CBSE, State, ISC/ICSE
ISC/ICSE Subjects taught
EVS, Political Science, Computer Science, Mathematics, Economics, Chemistry, Biology
CBSE Subjects taught
Computer Science, Mathematics, Chemistry, Biology, Economics, Geography, Political Science, History
Experience in School or College
Taught in School or College
No
State Syllabus Subjects taught
Economics, Computer Science, Chemistry, Political Science, History, Mathematics, Biology
Class Location
Student's Home
Tutor's Home
Online (video chat via skype, google hangout etc)
Board
CBSE, State, ISC/ICSE
ISC/ICSE Subjects taught
EVS, Political Science, Computer Science, Mathematics, Economics, Chemistry, Biology
CBSE Subjects taught
Computer Science, Mathematics, Chemistry, Biology, Economics, Geography, Political Science, History
Experience in School or College
Taught in School or College
No
State Syllabus Subjects taught
Economics, Computer Science, Chemistry, Political Science, History, Mathematics, Biology
Class Location
Student's Home
Tutor's Home
Online (video chat via skype, google hangout etc)
BSc Chemistry Subjects
BSc Computer Science Subjects
Operational Research, Microprocessors, Theory of Computations, Digital Electronics, Technical writing and communication in English, Programming Fundamentals, Data Structures, Discrete Structures, Calculus and Matrices, Artificial Intelligence, Operating Systems
Experience in School or College
Type of class
Regular Classes, Crash Course
Class strength catered to
Group Classes, One on one/ Private Tutions
Taught in School or College
No
BSc Branch
BSc Computer Science
Class Location
Student's Home
Tutor's Home
Online (video chat via skype, google hangout etc)
Teaches
Core Java
Certification training offered
Yes
Class Location
Student's Home
Tutor's Home
Online (video chat via skype, google hangout etc)
this is test message this is test message this is test message this is test message this is test message this is test message this is test message
"Write the chemical equation for the reaction involved in Cannizzaro reaction." in CBSE/Class 12/Science/Chemistry, Tuition/Class XI-XII Tuition (PUC)
2 C6H5CHO + KOH = C6H5CH2OH + C6H5COOK The oxidation product is a salt of a carboxylic acid and the reduction product is an alcohol.
"How can you distinguish between propanal and propanone?" in CBSE/Class 12/Science/Chemistry, Tuition/Class XI-XII Tuition (PUC)
(i) Propanal and propanone can be distinguished by the following tests. (a) Tollen's test: Propanal is an aldehyde. Thus, it reduces Tollen's reagent. But, propanone being a ketone does not reduce Tollen's reagent. (b) Fehling's test: Aldehydes respond to Fehling's test, but ketones do not. Propanal being an aldehyde reduces Fehling's solution to a red-brown precipitate of Cu2O, but propanone being a ketone does not. (c) Iodoform test: Aldehydes and ketones having at least one methyl group linked to the carbonyl carbon atom respond to iodoform test. They are oxidized by sodium hypoiodite (NaOI) to give iodoforms. Propanone being a methyl ketone responds to this test, but propanal does not. (ii) Acetophenone and Benzophenone can be distinguished using the iodoform test. Iodoform test: Methyl ketones are oxidized by sodium hypoiodite to give yellow ppt. of iodoform. Acetophenone being a methyl ketone responds to this test, but benzophenone does not. (iii) Phenol and benzoic acid can be distinguished by ferric chloride test. a. Ferric chloride test: Phenol reacts with neutral FeCl3 to form an iron-phenol complex giving violet colouration. But benzoic acid reacts with neutral FeCl3 to give a buff coloured ppt. of ferric benzoate. (iv) Benzoic acid and Ethyl benzoate can be distinguished by sodium bicarbonate test. Sodium bicarbonate test: Acids react with NaHCO3 to produce brisk effervescence due to the evolution of CO2 gas. Benzoic acid being an acid responds to this test, but ethylbenzoate does not. (v) Pentan-2-one and pentan-3-one can be distinguished by iodoform test. Iodoform test: Pentan-2-one is a methyl ketone. Thus, it responds to this test. But pentan-3-one not being a methyl ketone does not respond to this test. (vi) Benzaldehyde and acetophenone can be distinguished by the following tests. (a) Tollen's Test: Aldehydes respond to Tollen's test. Benzaldehyde being an aldehyde reduces Tollen's reagent to give a red-brown precipitate of Cu2O, but acetophenone being a ketone does not. (b) Iodoform test: Acetophenone being a methyl ketone undergoes oxidation by sodium hypoiodite (NaOI) to give a yellow ppt. of iodoform. But benzaldehyde does not respond to this test. (vii) Ethanal and propanal can be distinguished by iodoform test. Iodoform test: Aldehydes and ketones having at least one methyl group linked to the carbonyl carbon atom responds to the iodoform test. Ethanal having one methyl group linked to the carbonyl carbon atom responds to this test. But propanal does not have a methyl group linked to the carbonyl carbon atom and thus, it does not respond to this state.
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