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Atul Kashyap

Asansol, Asansol, India- 713301.

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Identity

Education

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Overview

I am Btech student. I love to teach. Teaching is passion. I explain the things with very simple example.

Demo Class

No

Languages Spoken

Maithili, Hindi, English

Education

Bachelor of Engineering (B.E.) from ASANSOL ENGINEERING COLLEGE -Pursuing.

Address

Asansol, Asansol, India- 713301.

BA Tuition Overview

BA Tuition

Field tutored for

Mathematics, Micro-Biology, Economics, History, Computer Science

BA Computer Science Subjects

Programming in JAVA, Programming Fundamentals using C++, Computer Networks, Artificial Intelligence, Computer System Architecture, Theory of Computation, Discrete Structures, Operating Systems, Data Structures, Database Management Systems, Design and Analysis of Algorithms

BA Mathematics Subjects

Group Theory, C++ Programming, Discrete Mathematics, Number Theory

Experience in School or College

Type of class

Crash Course, Regular Classes

Class strength catered to

Group Classes, One on one/ Private Tutions

Taught in School or College

No

BA Economics Subjects

Political Economy, Financial Economics, Economics of Health and Education, Economic History of India, Introductory Econometrics, Environmental Economics, Indian Economy, Public Economics

BA Micro- Biology Subjects

Cell Biology

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in BA Tuition

1

View all Classes

Reviews

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Answers by Atul Kashyap (2)

"Write the chemical equation for the reaction involved in Cannizzaro reaction." in   CBSE/Class 12/Science/Chemistry, Tuition/Class XI-XII Tuition (PUC)

2 C6H5CHO + KOH = C6H5CH2OH + C6H5COOK The oxidation product is a salt of a carboxylic acid and the reduction product is an alcohol.

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"How can you distinguish between propanal and propanone?" in   CBSE/Class 12/Science/Chemistry, Tuition/Class XI-XII Tuition (PUC)

(i) Propanal and propanone can be distinguished by the following tests. (a) Tollen's test: Propanal is an aldehyde. Thus, it reduces Tollen's reagent. But, propanone being a ketone does not reduce Tollen's reagent. (b) Fehling's test: Aldehydes respond to Fehling's test, but ketones do not. Propanal being an aldehyde reduces Fehling's solution to a red-brown precipitate of Cu2O, but propanone being a ketone does not. (c) Iodoform test: Aldehydes and ketones having at least one methyl group linked to the carbonyl carbon atom respond to iodoform test. They are oxidized by sodium hypoiodite (NaOI) to give iodoforms. Propanone being a methyl ketone responds to this test, but propanal does not. (ii) Acetophenone and Benzophenone can be distinguished using the iodoform test. Iodoform test: Methyl ketones are oxidized by sodium hypoiodite to give yellow ppt. of iodoform. Acetophenone being a methyl ketone responds to this test, but benzophenone does not. (iii) Phenol and benzoic acid can be distinguished by ferric chloride test. a. Ferric chloride test: Phenol reacts with neutral FeCl3 to form an iron-phenol complex giving violet colouration. But benzoic acid reacts with neutral FeCl3 to give a buff coloured ppt. of ferric benzoate. (iv) Benzoic acid and Ethyl benzoate can be distinguished by sodium bicarbonate test. Sodium bicarbonate test: Acids react with NaHCO3 to produce brisk effervescence due to the evolution of CO2 gas. Benzoic acid being an acid responds to this test, but ethylbenzoate does not. (v) Pentan-2-one and pentan-3-one can be distinguished by iodoform test. Iodoform test: Pentan-2-one is a methyl ketone. Thus, it responds to this test. But pentan-3-one not being a methyl ketone does not respond to this test. (vi) Benzaldehyde and acetophenone can be distinguished by the following tests. (a) Tollen's Test: Aldehydes respond to Tollen's test. Benzaldehyde being an aldehyde reduces Tollen's reagent to give a red-brown precipitate of Cu2O, but acetophenone being a ketone does not. (b) Iodoform test: Acetophenone being a methyl ketone undergoes oxidation by sodium hypoiodite (NaOI) to give a yellow ppt. of iodoform. But benzaldehyde does not respond to this test. (vii) Ethanal and propanal can be distinguished by iodoform test. Iodoform test: Aldehydes and ketones having at least one methyl group linked to the carbonyl carbon atom responds to the iodoform test. Ethanal having one methyl group linked to the carbonyl carbon atom responds to this test. But propanal does not have a methyl group linked to the carbonyl carbon atom and thus, it does not respond to this state.

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Atul Kashyap address

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BA Tuition

Field tutored for

Mathematics, Micro-Biology, Economics, History, Computer Science

BA Computer Science Subjects

Programming in JAVA, Programming Fundamentals using C++, Computer Networks, Artificial Intelligence, Computer System Architecture, Theory of Computation, Discrete Structures, Operating Systems, Data Structures, Database Management Systems, Design and Analysis of Algorithms

BA Mathematics Subjects

Group Theory, C++ Programming, Discrete Mathematics, Number Theory

Experience in School or College

Type of class

Crash Course, Regular Classes

Class strength catered to

Group Classes, One on one/ Private Tutions

Taught in School or College

No

BA Economics Subjects

Political Economy, Financial Economics, Economics of Health and Education, Economic History of India, Introductory Econometrics, Environmental Economics, Indian Economy, Public Economics

BA Micro- Biology Subjects

Cell Biology

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in BA Tuition

1

BTech Tuition

BTech Computer Science subjects

Computer Networks, Computer Architecture, Computer Organization & Design, Combinatorics, Java Programming, Microprocessors, Big Data Analytics, Compiler Design, Database Management Systems, Artificial Intelligence, Data Structures and Algorithms, Design and Analysis of Algorithms

BTech Branch

BTech 1st Year Engineering, BTech Computer Science Engineering, BTech Information Science Engineering

BTech Information Science subjects

Operating Systems, Database Systems, Big Data Analytics, Design & Analysis of Algorithms, Artificial Intelligence, Computer Networks, Computer Organization & Microprocessor Systems, Internet of Things, Data Structures and Algorithms, Object Oriented Programming

Experience in School or College

Type of class

Crash Course, Regular Classes

Class strength catered to

Group Classes, One on one/ Private Tutions

BTech Mechantronics subjects

Algorithms

Taught in School or College

No

BTech 1st Year subjects

Engineering Physics, Computer science, Engineering Mathematics (M1), Basic Electronics, Biology For Engineers, Environmental Studies, Engineering Chemistry, Communication Skills, Advanced Mathematics (M2)

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in BTech Tuition

1

BCA Tuition

Experience in School or College

BCA Subject

Object Oriented Technologies, Programming in C++ , Computer Networks , Database Management Systems , Operating System Concepts and Networking Management , Java Programming, Problem Solving and Programming , Computer Architecture, Operation Research, Digital Electronics, Data structures, C Language Programming, Microprocessor, Mathematics, Algorithm Design

Type of class

Crash Course, Regular Classes

Class strength catered to

Group Classes, One on one/ Private Tutions

Taught in School or College

No

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in BCA Tuition

1

C Language Classes

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in C Language Classes

1

Engineering Entrance Coaching classes

Engineering Entrance Exams

IIT JEE Coaching Classes, GATE Coaching Classes

IITJEE Coaching

IIT JEE Crash Course, IIT JEE Foundation Course, IIT JEE Mains Coaching, IIT JEE Integrated Coaching

Type of class

Crash Course, Regular Classes

IIT-JEE Subjects

Chemistry

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Engineering Entrance Coaching classes

1

Class XI-XII Tuition (PUC)

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Economics, Mathematics, EVS, Political Science, Chemistry, Computer Science, Biology

CBSE Subjects taught

History, Computer Science, Chemistry, Biology, Geography, Economics, Mathematics, Political Science

Experience in School or College

Taught in School or College

No

State Syllabus Subjects taught

History, Chemistry, Biology, Mathematics, Political Science, Computer Science, Economics

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

BSc Tuition

BSc Chemistry Subjects

BSc Computer Science Subjects

Programming Fundamentals, Operating Systems, Digital Electronics, Technical writing and communication in English, Theory of Computations, Artificial Intelligence, Calculus and Matrices, Discrete Structures, Data Structures, Microprocessors, Operational Research

Experience in School or College

Type of class

Crash Course, Regular Classes

Class strength catered to

Group Classes, One on one/ Private Tutions

Taught in School or College

No

BSc Branch

BSc Computer Science

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Java Training Classes

Teaches

Core Java

Certification training offered

Yes

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

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No Reviews yet! Be the first one to Review

"Write the chemical equation for the reaction involved in Cannizzaro reaction." in   CBSE/Class 12/Science/Chemistry, Tuition/Class XI-XII Tuition (PUC)

2 C6H5CHO + KOH = C6H5CH2OH + C6H5COOK The oxidation product is a salt of a carboxylic acid and the reduction product is an alcohol.

0
|
0

"How can you distinguish between propanal and propanone?" in   CBSE/Class 12/Science/Chemistry, Tuition/Class XI-XII Tuition (PUC)

(i) Propanal and propanone can be distinguished by the following tests. (a) Tollen's test: Propanal is an aldehyde. Thus, it reduces Tollen's reagent. But, propanone being a ketone does not reduce Tollen's reagent. (b) Fehling's test: Aldehydes respond to Fehling's test, but ketones do not. Propanal being an aldehyde reduces Fehling's solution to a red-brown precipitate of Cu2O, but propanone being a ketone does not. (c) Iodoform test: Aldehydes and ketones having at least one methyl group linked to the carbonyl carbon atom respond to iodoform test. They are oxidized by sodium hypoiodite (NaOI) to give iodoforms. Propanone being a methyl ketone responds to this test, but propanal does not. (ii) Acetophenone and Benzophenone can be distinguished using the iodoform test. Iodoform test: Methyl ketones are oxidized by sodium hypoiodite to give yellow ppt. of iodoform. Acetophenone being a methyl ketone responds to this test, but benzophenone does not. (iii) Phenol and benzoic acid can be distinguished by ferric chloride test. a. Ferric chloride test: Phenol reacts with neutral FeCl3 to form an iron-phenol complex giving violet colouration. But benzoic acid reacts with neutral FeCl3 to give a buff coloured ppt. of ferric benzoate. (iv) Benzoic acid and Ethyl benzoate can be distinguished by sodium bicarbonate test. Sodium bicarbonate test: Acids react with NaHCO3 to produce brisk effervescence due to the evolution of CO2 gas. Benzoic acid being an acid responds to this test, but ethylbenzoate does not. (v) Pentan-2-one and pentan-3-one can be distinguished by iodoform test. Iodoform test: Pentan-2-one is a methyl ketone. Thus, it responds to this test. But pentan-3-one not being a methyl ketone does not respond to this test. (vi) Benzaldehyde and acetophenone can be distinguished by the following tests. (a) Tollen's Test: Aldehydes respond to Tollen's test. Benzaldehyde being an aldehyde reduces Tollen's reagent to give a red-brown precipitate of Cu2O, but acetophenone being a ketone does not. (b) Iodoform test: Acetophenone being a methyl ketone undergoes oxidation by sodium hypoiodite (NaOI) to give a yellow ppt. of iodoform. But benzaldehyde does not respond to this test. (vii) Ethanal and propanal can be distinguished by iodoform test. Iodoform test: Aldehydes and ketones having at least one methyl group linked to the carbonyl carbon atom responds to the iodoform test. Ethanal having one methyl group linked to the carbonyl carbon atom responds to this test. But propanal does not have a methyl group linked to the carbonyl carbon atom and thus, it does not respond to this state.

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Atul Kashyap conducts classes in BA Tuition, BCA Tuition and BSc Tuition. Atul is located in Asansol, Asansol. Atul takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. He has 1 years of teaching experience . Atul is pursuing Bachelor of Engineering (B.E.) from ASANSOL ENGINEERING COLLEGE. HeĀ is well versed in Maithili, Hindi and English.

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