Anand Dodrajka

Belgachia Birendranagar Colony, Kolkata, India - 700037

Belgachia Birendranagar Colony, Kolkata, India - 700037.

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Having a versatile experience in teaching all categories of students across diverse boards.

Crash course just before the exams is a special feature.

Marathon classes on the penultimate day of exam is an additional benefit to students.

Crash course just before the exams is a special feature.

Marathon classes on the penultimate day of exam is an additional benefit to students.

Bengali Proficient

Hindi Proficient

English Proficient

Army Institute of management 2009

Master of Business Administration (M.B.A.)

Belgachia Birendranagar Colony, Kolkata, India - 700037

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BCom Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in BCom Tuition

5

BCom Subject

Banking and Insurance, Financial Management, Business Mathematics and Statistics

Type of class

Crash Course, Regular Classes

Class strength catered to

Group Classes

Taught in School or College

No

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No Reviews yet! Be the first one to Review

Answered on 23 Jul Tuition

No additional courses need to be studied. You need to develop patience as are teaching primary Kids. Be calm. Slowly all shall sink in you; it's only a matter one student.

Like 1

Answers 74 Comments Answered on 19 Jun CBSE/Class 10/Mathematics/UNIT II: Algebra/Pair of linear equations in two variable/NCERT Solutions/Exercise 3.3

7/9.. let numerator be X and denominator be y so from condition 1 we have X+2/y+2= 9/11.. or 11x+22=9y+18 ....or 11x-9y=-4... equation 1.. Similarly, from condition 2 we have X+3/y+3=5/6.. or 6x+18=5y+15..or 6x-5y= -3... equation 2... Solving both the equation for X and y we have X=7 and y =9... Hence... ...more

7/9.. let numerator be X and denominator be y so from condition 1 we have X+2/y+2= 9/11..

or 11x+22=9y+18 ....or 11x-9y=-4... equation 1.. Similarly, from condition 2 we have X+3/y+3=5/6.. or 6x+18=5y+15..or

6x-5y= -3... equation 2...

Solving both the equation for X and y we have X=7 and y =9...

Hence the fraction 7/9

Like 0

Answers 4 Comments Answered on 08 Apr Tuition

Please try to understand that one tutor can't teach all the papers as all require different level of expertise. So better try out subject wise or a combination of subjects with each tutor.

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Answers 64 Comments Anand DodrajkaDirections

x BCom Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in BCom Tuition

5

BCom Subject

Banking and Insurance, Financial Management, Business Mathematics and Statistics

Type of class

Crash Course, Regular Classes

Class strength catered to

Group Classes

Taught in School or College

No

BBA Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in BBA Tuition

5

BBA Subject

Mathematics, Statistics, Financial Management

Type of class

Crash Course, Regular Classes

Class strength catered to

Group Classes

Taught in School or College

No

Class 10 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 10 Tuition

5

Board

CBSE, State, ICSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Chemistry, Mathematics, Physics

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics

Class 9 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 9 Tuition

5

Board

CBSE, State, ICSE

CBSE Subjects taught

Accountancy, Mathematics

ICSE Subjects taught

Chemistry, Mathematics, Physics

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics

CA Coaching classes 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in CA Coaching classes

2

Coaching provided for

CPT

CA_CPT_Subjects

General English, General Economics, Quantitative aptitude, Fundamentals OF Accounting

Teaching Experience in detail in CA Coaching classes

First hand experience in teaching CPT students

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No Reviews yet! Be the first one to Review

Answered on 23 Jul Tuition

Like 1

Answers 74 Comments Answered on 19 Jun CBSE/Class 10/Mathematics/UNIT II: Algebra/Pair of linear equations in two variable/NCERT Solutions/Exercise 3.3

7/9.. let numerator be X and denominator be y so from condition 1 we have X+2/y+2= 9/11.. or 11x+22=9y+18 ....or 11x-9y=-4... equation 1.. Similarly, from condition 2 we have X+3/y+3=5/6.. or 6x+18=5y+15..or 6x-5y= -3... equation 2... Solving both the equation for X and y we have X=7 and y =9... Hence... ...more

7/9.. let numerator be X and denominator be y so from condition 1 we have X+2/y+2= 9/11..

or 11x+22=9y+18 ....or 11x-9y=-4... equation 1.. Similarly, from condition 2 we have X+3/y+3=5/6.. or 6x+18=5y+15..or

6x-5y= -3... equation 2...

Solving both the equation for X and y we have X=7 and y =9...

Hence the fraction 7/9

Like 0

Answers 4 Comments Answered on 08 Apr Tuition

Like 0

Answers 64 Comments Share this Profile

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