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Kapil Jha Class 9 Tuition trainer in Ahmedabad

Kapil Jha

IIT Foundation Expert

Chandlodia, Ahmedabad, India - 382481.

Contact
Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

Details verified of Kapil Jha✕

Identity

Education

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Identity is verified based on matching the details uploaded by the Tutor with government databases.

Overview

I am an IIT Graduate, 15 Years of Experience. Good command over Physics and Maths.

Languages Spoken

Hindi

English Proficient

Education

IIT Roorkee 2000

Bachelor of Technology (B.Tech.)

Address

Chandlodia, Ahmedabad, India - 382481

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Teaches

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

15

Board

ICSE, CBSE

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Chemistry, Mathematics, Physics

Taught in School or College

No

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

15

Board

ICSE, CBSE

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Chemistry, Mathematics, Physics

Taught in School or College

No

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Engineering Entrance Exams

IIT JEE Coaching Classes

Courses

IX & X Coaching Classes for Maths & Science by an IITian
LIVE
10 Hours
View this Course

Reviews

No Reviews yet! Be the first one to Review

FAQs

1. Which school boards of Class 10 do you teach for?

ICSE, CBSE

2. Do you have any prior teaching experience?

No

3. Which classes do you teach?

I teach Class 10 Tuition, Class 9 Tuition and Engineering Entrance Coaching Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 15 years.

Contact

Answers by Kapil Jha (1)

Answered on 28/06/2017 Learn Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching +1 Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/Physics

A block is kept on the floor of an elevator at rest. The elevator starts descending with an acceleration... ...more
A block is kept on the floor of an elevator at rest. The elevator starts descending with an acceleration 12 m/s. Find the displacement of the block during the first 0.2 s after the start?

s=Ut+(1/2)at^2 Here U=0, t=0.2 Sec, and a=-12 m/s^2 {-ve sign is because its descending object} So Displacement S = (0*0.2) + 1/2 (-12*0.2*0.2) =-0.24 m
Answers 25 Comments
Dislike Bookmark

Contact

Teaches

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

15

Board

ICSE, CBSE

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Chemistry, Mathematics, Physics

Taught in School or College

No

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

15

Board

ICSE, CBSE

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Chemistry, Mathematics, Physics

Taught in School or College

No

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Engineering Entrance Exams

IIT JEE Coaching Classes

Courses

IX & X Coaching Classes for Maths & Science by an IITian
LIVE
10 Hours
View this Course
No Reviews yet! Be the first one to Review

Answers by Kapil Jha (1)

Answered on 28/06/2017 Learn Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching +1 Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/Physics

A block is kept on the floor of an elevator at rest. The elevator starts descending with an acceleration... ...more
A block is kept on the floor of an elevator at rest. The elevator starts descending with an acceleration 12 m/s. Find the displacement of the block during the first 0.2 s after the start?

s=Ut+(1/2)at^2 Here U=0, t=0.2 Sec, and a=-12 m/s^2 {-ve sign is because its descending object} So Displacement S = (0*0.2) + 1/2 (-12*0.2*0.2) =-0.24 m
Answers 25 Comments
Dislike Bookmark

Contact

Kapil Jha describes himself as IIT Foundation Expert. He conducts classes in Class 10 Tuition, Class 9 Tuition and Engineering Entrance Coaching. Kapil is located in Chandlodia, Ahmedabad. Kapil takes Regular Classes- at his Home and Online Classes- via online medium. He has 15 years of teaching experience . Kapil has completed Bachelor of Technology (B.Tech.) from IIT Roorkee in 2000. He is well versed in Hindi and English.

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